131+108+107+110+x=540
456 + x = 540
-456 -456
x = 84
<h3><u>The function used to find the perimeter of a square, represented by y, given the length of a side, represented by x is: y = 4x</u></h3>
<em><u>Solution:</u></em>
Let "y" be the perimeter of square
Let the length of side be "x"
From given,
The perimeter of a square is the product of four and the length of a side
Which means,
![\text{Perimeter of square } = 4 \times \text{ length of side }](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%20of%20square%20%7D%20%3D%204%20%5Ctimes%20%5Ctext%7B%20length%20of%20side%20%7D)
Substituting the given variables,
![y = 4 \times x\\\\y = 4x](https://tex.z-dn.net/?f=y%20%3D%204%20%5Ctimes%20x%5C%5C%5C%5Cy%20%3D%204x)
Thus perimeter of square is y = 4x
Answer:
Step-by-step explanation:
Linear is C .
Quadratic is A
Exponential is B
Answer:
Step-by-step explanation:
2. 2c(7c + 1)
3. stays as is
4. 2x^3y^4(4 - 11x^2y^2)
5. ab(10ab + 9b - a)
6. 3m^2(7m^4n^2+2m^2n+5)
7. (a - 8)(a + 8)
8. (y - 17)(y + 17)
9. stays as is
10. (1 - 5n)(1 + 5n)
11. (4x - 7y)(4x + 7y)
12. (w^2 - 10)(w^2 + 10)
13. (c - 9d)(c + 9d)
14. (14a - b)(14a + b)
Answer:
Only C
Step-by-step explanation:
A = 3D
J = 7 + D
A: Alice doesn't necceserily have more stamps than Jane ( Jane could have 8 + 4 = 12 stamps, and Alice would have 3 + 4 = 7) (This is false)
B: Jane will ALWAYS have 7 more stamps than Doris (if all values are increased by same amount). (This is false)
C: The Sum of Alice and Doris is D + 3D = 4D, so C is true