Answer:
Step-by-step explanation:
From table 1,
f(x) = bˣ
For x = -1,
f(-1) = 0.5
0.5 = (b)⁻¹
b = 
b = 2
For x = 1.585,
f(1.585) = 3
3 = 
3 = 
For x = 2.585,
f(2.585) = 
= 
= 4 × 1.5 [Since, ]
= 6
From table 2,
g(x) = 
For x = 0.5,
g(0.5) = -1
-1 = 
b⁻¹ = 0.5
b = 2
For x = 2,
g(2) = 1
1 = 
For x = 6,
g(6) = 2.585
2.585 = 
2.585 = 
2.585 = 
2.858 - 1 = 
For x = 3,
g(3) =
g(3) = 1.585
Answer:
1 gamma = 15/8 alphas
Step-by-step explanation:
so we start by finding out what 1 gamma and 1 beta equals.
we know 4 gammas = 5 betas so if we divide by four on both sides we get:
1 gamma = 5/4 betas. we can apply that same procedure to 2 betas = 3 alphas and get 1 beta = 3/2 alphas
we know that 1 gamma = 5/4 betas and 1 beta = 3/2 alphas so how many alphas = 5/4 betas? using a proportion of ((3/2)/1) = ((x)/(5/4)) we can find that 5/4 betas = 15/8 alphas
therefore we know 1 gamma = 15/8 alphas or 1 and 7/8 alphas
Answer:
0.0016283
Step-by-step explanation:
Given that:
Proportion of defective bulbs, p = 30% = 0.3
Sample size, n = 19 bulbs
Probability that the lot will pass inspection :
P(none of the 19 is defective) Or P(only one of the 19 is defective)
P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19
0.7^19 = 0.0011398
P(only one of the 19 is defective) :
P(1 defective) * P(18 not defective )
(0.3) * (1 - 0.3)^18
0.3 * 0.7^18
0.3 * 0.001628413597910449 = 0.0004885
Hence,
P(none of the 19 is defective) + P(only one of the 19 is defective)
0.0011398 + 0.0004885) = 0.0016283
Take the tax (6$) and divide it by the pretax(75$) and take that number and multiply it by 100 and you get your percentage (8%)
Answer:
x=11
Step-by-step explanation:
4x+11=5x (angle adb and edf are the same)
11=5x-4x
11=x
x=11
if you want you can check by doing...
(14*11-29)+(5*11)=180
