13/15 of her allowance was spent in total.
To solve this, you'd need to find the least common denominator (LCD) so that both fractions have the same number on the bottom. In this case, the first number that you could get with 5 and 3 was 15.
Next, you'd have to multiply the numerator by the same amount as the denominator, so that the fractions are proportionate. So, for 1/5, since we had to multiply 5 by 3 to get 15, we'd multiply 1 by 3 as well, giving us 3/15. Doing the same with 2/3, we'd get 10/15.
Then, you add the two fractions together (10/15 + 3/15 = 13/15).
Now, in any other case, you could probably simplify the fraction after you've solved the problem. If we got 12/15 instead of 13/15, then we could simplify that to 4/5, since both 12 and 15 are divisible by 3. But in this case, this is the simplest form of that fraction.
Hope this helped!!!
5.5, divide 5,500 by 1,000 to get 5.5 kg.
Degrees Fahrenheit = (1.8 * -35) +32
Degrees Fahrenheit = -31
Formulas and temperature converter are here:
http://www.1728.org/convtmp2.htm
Answer:
<u>James sold 300 tickets for adults</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Number of tickets sold by James = 450
Cost of a child ticket = $ 2
Cost of an adult ticket =$ 5
Amount of money collected by James after selling the 450 tickets for the community play = $ 1,800
2. How many tickets for adults did James sell?
x = Number of adult tickets James sold
450 - x = Number of children tickets James sold
For solving for x, we write this equation:
5x + 2 * (450 - x) = 1,800
5x + 900 - 2x = 1,800
3x = 1,800 - 900
3x = 900
x = 900/3 = 300
450 - x = 450 - 300 = 150
<u>James sold 300 tickets for adults and 150 for children</u>
A. The area of a square is given as:
<span>A = s^2 </span>
Where s is a measure of a side of a square. s = (2 x – 5)
therefore,
<span>A =
(2 x – 5)^2 </span>
Expanding,
A =
4 x^2 – 20 x + 25
<span>B.
The degree of a polynomial is the highest exponent of the variable x, in this case
2. Therefore the expression obtained in part A is of 2nd degree.</span>
Furthermore,
polynomials are classified according to the number of terms in the expression.
There are 3 terms in the expression therefore it is classified as a trinomial.
<span>C.
The closure property demonstrates that during multiplication or division, the
coefficients and power of the variables are affected while during
multiplication or division, only the coefficients are affected while the power
remain the same.</span>
