Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
Answer:
whats the question?
Step-by-step explanation:
I don't get the question so what is the question?
The number of pieces made from rod is 49
<h3><u>Solution:</u></h3>
Given that A metal rod will be cut into pieces that are each 1/56 meters long
The rod is 7/8 meters long.
<em><u>To find: number of peices made from rod</u></em>
The number of peices made from rod can be calculated by dividing the total length of rod by length of each piece
Here total length of rod = 
meters
length of each piece to be made = 
meters
Substituting the values in above formula, we get
So the number of pieces made from rod is 49
Answer:
There is no function posted with this question, but slope means how steep a line is. The slope is also known as the average rate of change.
Step-by-step explanation:
Look for the calculator for algebra online
