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3 years ago

Part F – Model, solve, and interpret the word problem

Mathematics

1 answer:

ira [324]3 years ago

7 0

Answer:

are just rusty, or if you are using this book to supplement topics you are currently ... Every problem in 501 Math Word Problems has a complete answer explanation. ... The temperature at 6 p.m. was 31°F. By midnight, it had dropped 40 °F. First, find the fraction of the book that Justin read the first 3 days by.

Step-by-step explanation:

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How do you find the area of a circle?

sveta [45]

Answer:

A=πr^2

Step-by-step explanation:

A=Area

r=Radius

5 0

3 years ago

Read 2 more answers

i have 60+8x=108 x=6 but for the other equation i dont know how to get rid of the 3x to solve for the y.

LUCKY_DIMON [66]

Angle a is congurent to angle e, so 60+8x=108
same with c and g.
so 8y-3x=62
just plug in x for there (6)
so 8y-24=62
then 8y=88
y=11

8 0

4 years ago

Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at <em>x</em> = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$

5 0

3 years ago

Express the ratios as a fraction without reducing.

VLD [36.1K]

Answer:

A) 6/13 B) 7/40 C) 45/36 D) 37/43

Step-by-step explanation:

4 0

3 years ago

P(S) = 3/5<br> P(T) = 1/3<br> If S and T are mutually exclusive events, find P(S or T).

Strike441 [17]

Answer:

14/15

Step-by-step explanation:

P(S or T) = P(S) + P(T) = 3/5 + 1/3

= 9/15 + 5/15 = 14/15

7 0

2 years ago