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forsale [732]
3 years ago
12

NEED HELP QUICK!!! ∆PQR ~ ∆CDR. m∠C = 2(x +20)º, m∠PQR = (4x), and m∠P = (5x - 5)º. Find x.

Mathematics
1 answer:
Tanya [424]3 years ago
8 0
What! i dont know this math yet:(
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HELP! look at image pls
dalvyx [7]
The answers C I’m not sure if I’m too late
8 0
3 years ago
Use the stacked box and whisker plot in the diagram below. What conclusion can be made about the median of the two data sets?
iren [92.7K]

ANSWER

The median for school #1 is greater

EXPLANATION

In a box and whisker plot, we have the following information about the data set,

The vertical line inside the box is the median.

In this problem, the median for school #1 is about 82, while the median for school #2 is about 80 (between 78 and 82). Therefore, the median for school #1 is greater.

7 0
2 years ago
The automaker of your new car recommended an oil change following the 5,000 miles and then every 3,000 miles thereafter.if you p
Rus_ich [418]

Answer:

3 oil changes

Step-by-step explanation:

1. Find an equation that represents this word problem: 3000x + 5000 = y

Where y = the # of miles total. y = 250 miles/week * 52 weeks/year = 13000 miles.

2. Solve for x: 3000x + 5000 = 13000   3000x=8000

3. x = 8/3 integer round down x = 2 oil changes, but plus the one after 5000 miles is a total of 3 oil changes that year

3 0
3 years ago
In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
damaskus [11]

Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

expected value= 1/38 * $315 + 37/38*(-$9) = $8.2894 - $8.7631

expected value= -$0.47368

You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

number of roll * expected value

1000 timer * -$0.47368/time= -$473.68

You are expected to lose $473.68 if you play the game 1000 times.

6 0
3 years ago
Someone can help me this is really hard for me to do(thanks)
Kipish [7]
SA= 4• pi• radius ^2 = 4•25•pi= 100 pi
Answer C
4 0
3 years ago
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