Answer:
47.4 ;
50
Step-by-step explanation:
Given the data :
X ($) : 85 139 161 175 85 133 149 145 136 131 290 235 132 149 322 214 105 90 162 229 121 113 149 126139 118 156 214 172 87 172 230 195 126 128 142 118 139
The smallest class interval :
Range / number of classes
Number of classes to use = 5
Range = Maximum - Minimum = (322 - 85) =237
Hence, smallest class interval :
237 / 5 = 47.4
A better class interval would be, one without decimal, rounded to the nearest 10; this will be easier and make more statistical sense
Hence, smallest class interval rounded to the nearest 10 :
47.4 = 50 (nearest 10)
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
90+55+75+60+80+90=450
450/6=75
Answer:
Looking at the example Alana will walk. 15.23 miles in two days
step-by-step explanation:
Looking at the example and using place value system
8.63 + 6.60= 15.23 miles
Answer:
4/3
Step-by-step explanation:
