Answer/Step-by-step explanation:
Recall: SOHCAHTOA
1. Reference angle = 70°
Adjacent side = x
Hypotenuse = 6 cm
Apply CAH. Thus,
Cos 70 = adj/hyp
Cos 70 = x/6
6 × cos 70 = x
2.05 = x
x = 2.05 cm
2. Reference angle = 45°
Adjacent side = x
Hypotenuse = 1.3 m
Applying CAH, we would have the following ratio:
Cos 45 = adj/hyp
Cos 45 = x/1.3
1.3 × cos 45 = x
0.92 = x
x = 0.92 m
3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.
Answer:
c
Step-by-step explanation
im sorry for not explaining im not good at that just trust me
A(n,s)=(ns^2)/(4tan(180/n)), n=number of sides, s=side length
A(8,4.6)=(8*4.6^2)/(4tan22.5)
A(8,4.6)=42.32/tan22.5 m (exact)
A(8, 4.6)≈102.17 m^2 (to nearest hundredth of a square meter)
Answer:
where is the figure?
Step-by-step explanation:
I can't see a figure
