Answer:
81, 27, 48, 77
Step-by-step explanation:
Answer:
y= 1 and x=-2
Step-by-step explanation:
Since they both equal y, you can equal them to each other:
x + 3 = 2x + 5
Then solve:
x - x + 3 = 2x - x + 5
3 - 5 = x + 5 - 5
-2 = x
Substitute x in either equation to solve for y:
y = (-2) +3
y = 1
Or the other equation:
y = 2(-2) + 5
y = -4 + 5
y = 1
hope this helps :)
A = 11, b = 7
You just needed to multiply the terms together
![{\bold{\red{\huge{\mathbb{QUESTION}}}}}](https://tex.z-dn.net/?f=%20%7B%5Cbold%7B%5Cred%7B%5Chuge%7B%5Cmathbb%7BQUESTION%7D%7D%7D%7D%7D%20)
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?
![\bold{ \red{\star{\blue{GIVEN }}}}](https://tex.z-dn.net/?f=%5Cbold%7B%20%5Cred%7B%5Cstar%7B%5Cblue%7BGIVEN%20%7D%7D%7D%7D)
RADIUS = 2
CHORD = 2
RADIUS --> XY , XZ , WX
( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)
![\bold{\blue{\star{\red{TO \: \: FIND}}}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cblue%7B%5Cstar%7B%5Cred%7BTO%20%5C%3A%20%20%5C%3A%20FIND%7D%7D%7D%7D)
THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.
![\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}](https://tex.z-dn.net/?f=%20%5Cbold%7B%20%20%5Cgreen%7B%20%5Cstar%7B%20%5Corange%7BFORMULA%20%5C%3A%20%20USED%7D%7D%7D%7D)
AREA COVERED BY THE ANGLE IN A SEMI SPHERE
![AREA = ANGLE \: \: IN \: \: RADIAN \times RADIUS](https://tex.z-dn.net/?f=AREA%20%3D%20ANGLE%20%20%20%5C%3A%20%5C%3A%20IN%20%20%5C%3A%20%5C%3A%20%20RADIAN%20%20%5Ctimes%20RADIUS)
![\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}](https://tex.z-dn.net/?f=%20%5Chuge%5Cmathbb%7B%5Cred%20A%20%5Cpink%7BN%7D%5Cpurple%7BS%7D%20%5Cblue%7BW%7D%20%5Corange%7BER%7D%7D)
Total Area Of The Semi Sphere:-
![AREA = \pi \times radius \\ \\ AREA = \pi \times 2 = 2\pi](https://tex.z-dn.net/?f=AREA%20%3D%20%20%20%5Cpi%20%5Ctimes%20radius%20%20%5C%5C%20%20%5C%5C%20AREA%20%3D%20%5Cpi%20%5Ctimes%202%20%3D%202%5Cpi)
Area Under Unshaded Part .
Given a triangle with each side 2 units.
This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian
So AREA :-
![AREA = \frac{\pi}{3} \times radius \\ \\ AREA = \frac{\pi}{3} \times 2 \\ \\ AREA = \frac{2\pi}{3}](https://tex.z-dn.net/?f=AREA%20%3D%20%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20%20%5Ctimes%20radius%20%5C%5C%20%20%5C%5C%20AREA%20%3D%20%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20%20%5Ctimes%202%20%5C%5C%20%20%5C%5C%20AREA%20%3D%20%20%5Cfrac%7B2%5Cpi%7D%7B3%7D%20)
![\green{Now:- } \\ \green{ \: Area \: Under \: Unshaded \: Part }](https://tex.z-dn.net/?f=%20%5Cgreen%7BNow%3A-%20%7D%20%5C%5C%20%20%5Cgreen%7B%20%5C%3A%20Area%20%20%5C%3A%20Under%20%5C%3A%20%20Unshaded%20%5C%3A%20%20Part%20%7D)
Total Area - Area Under Unshaded Part
![Area= 2\pi - \frac{2\pi}{3} \\ Area = \frac{6\pi - 2\pi}{3} \\ Area = \frac{4\pi}{3} \: \: ans](https://tex.z-dn.net/?f=%20Area%3D%202%5Cpi%20-%20%20%5Cfrac%7B2%5Cpi%7D%7B3%7D%20%20%5C%5C%20Area%20%3D%20%20%5Cfrac%7B6%5Cpi%20-%202%5Cpi%7D%7B3%7D%20%20%20%5C%5C%20Area%20%3D%20%20%5Cfrac%7B4%5Cpi%7D%7B3%7D%20%20%5C%3A%20%20%5C%3A%20ans)
![\red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star](https://tex.z-dn.net/?f=%20%5Cred%20%5Cstar%7BThanks%20%5C%3A%20%20And%20%20%5C%3A%20Brainlist%7D%20%20%5Cblue%5Cstar%20%5C%5C%20%20%5Cgreen%5Cstar%20%20If%20%5C%3A%20%20U%20%20%5C%3A%20Liked%20%5C%3A%20%20My%20%20%5C%3A%20Answer%20%5Cpurple%20%5Cstar)