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nlexa [21]
2 years ago
10

ANSWER THIS ASAP PLS SHOW WORK ☹☹☹

Mathematics
1 answer:
Sliva [168]2 years ago
8 0

Answer:

Square 63 is, 7.93725393319

Step-by-step explanation:

I will do more later be patient :)

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2. The radius of a circle is 9 cm. Find the area of the circle
MatroZZZ [7]

Answer:

Area of a Circle = 254.34 cm²

Step-by-step explanation:

Area of a Circle = π r²

Area of a Circle = 3.14 * 9²

Area of a Circle = 254.34 cm²

3 0
3 years ago
Does the budgeted amount cover the actual amount for expenses, savings, and emergencies?
rosijanka [135]

Answer:

No its short 207

Step-by-step explanation:

Took the test on UsaTestPrep got it right :)

Bye loves <3

8 0
2 years ago
Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8
Gekata [30.6K]
First, let (x,y) be a point in our parabola. Since we know that the focus of our parabola is  the point (0,8), we are going to use the distance formula to find the distance between the two points:
\sqrt{(x-0)^{2}+(y-8)^{2}}

Next, we are going to find the distance between the directrix and the point in our parabola. Remember that the distance between a point (x,y) of a parabola and its directrix, y=c, is: |y-c|. Since our directrix is y=-8, the distance to our point will be:
|y-(-8)|
|y+8|

Now, we are going to equate those two distances, and square them to get rid of the square root and the absolute value:
\sqrt{(x-0)^{2}+(y-8)^{2}}=|y+8|
(\sqrt{(x-0)^{2}+(y-8)^{2}})^{2}=|y+8|^{2}
(x-0)^{2}+(y-8)^{2}=y+8

Finally, we can expand and solve for y:
x^2+y^2-16y+64=y^2+16y+64
x^{2}-16y=16y
32y=x^{2}
y= \frac{1}{32} x^2

We can conclude that t<span>he standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8 is </span>y= \frac{1}{32} x^{2}

3 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem.
slamgirl [31]

Answer:

h = -t+20

After 8 hours the candle will be 12 inches

Step-by-step explanation:

We have 2 points (time, inches)

 (3,17)  and (5,15)

We can find the slope

m = (y2-y1)/(x2-x1)

   = (15-17)/(5-3)

   = -2/2

   = -1

We can use point slope form

y-y1 = m(x-x1)

Replace y with h and x with t

h-17 = -1 (t-3)

Distribute

h-17 = -t+3

Add 17 to each side

h-17+17 = -t+3+17

h = -t+20

3 0
3 years ago
LK is tangent to circle J at point K. Circle J is shown. Line segment J K is a radius. Line segment K L is a tangent that inters
Evgen [1.6K]

Answer:

(B)r=\dfrac{85}{12}

Step-by-step explanation:

Given a circle centre J

Let the radius of the circle =r

LK is tangent to circle J at point K

From the diagram attached

  • LX=6
  • Radius, XJ=JK=r
  • LK=11

Theorem: The angle between a tangent and a radius is 90 degrees.

By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.

Using Pythagoras Theorem:

(6+r)^2=r^2+11^2\\(6+r)(6+r)=r^2+121\\36+6r+6r+r^2=r^2+121\\12r=121-36\\12r=85\\r=\dfrac{85}{12}

The length of the radius, r=\dfrac{85}{12}

8 0
3 years ago
Read 2 more answers
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