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3 years ago

Solve For X In Both Questions Please!

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

6 0

Answer:

take 42 degree as reference angle

using sine rule

sin 42=opposite/hypotenuse

0.66=x/23

23*0.66=x

15.18=x

15.2=x

take x degree as reference angle

using cos rule

cosx=adjacent/hypotenuse

cosx=29/42

cosx=0.69

cos 46 =0.69

therefore x=46 degree

Step-by-step explanation:

Naily [24]3 years ago

4 0

After the dog crossed the streeet maybe

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PLS need help 0.85= y/0.8 - 0.1 find y

zvonat [6]

Answer:0.76

Step-by-step explanation:

5 0

2 years ago

Consider parent function f(x)=e^x and the transformes function g(x)= -1/2e^3x+4, quantitatively explain the transformations to t

kolezko [41]

Answer: reflection across the x-axis

vertical shrink by a factor of 1/2

horizontal shrink by a factor of 1/3

vertical shift up 4 units

<u>Step-by-step explanation:</u>

$\text{Note:}\ g(x) = -Ae^{Bx-C}+D\\\bullet \quad \text{- represents a reflection across the x-axis}\\\\\bullet \quad \text{A represent a vertical stretch by a factor of A (shrink if}\ |A| < 1)\\\\\bullet \quad \text{B represents a horizontal stretch by a factor of}\ \dfrac{1}{B}\ (\text{shrink if}\ |B| >1) \\\\\bullet \quad \text{C represents a horizontal shift of C units}\ (\text{+ is right, - is left}) \\\\\bullet \quad \text{D represents a vertical shift of D units}\ (\text{+ is up, - is down})$

$\text{Parent function:}\ f(x)=e^x\\\text{Transformed function:}\ g(x)=-\dfrac{1}{2}e^{3x}+4\\$

The transformed function has the following:

Negative: reflection across the x-axis

A = 1/2 vertical shrink by a factor of 1/2

B = 3 horizontal shrink by a factor of 1/3

C = 0 no horizontal shift

D = 4 vertical shift of 4 units up

6 0

3 years ago

Officials begin to release water from a full man-made lake at a rate that would empty the lake in 10 weeks, but a river that can

Romashka [77]

Answer:

It takes 20 weeks to empty the lake

Step-by-step explanation:

Some rate, let's call it $R_{empty}$ empties the lake in 10 weeks and a river (with rate $R_{river}$ can fill the lake in 20 weeks. The idea behind the solution of this type of problem is always set the rate to the same units. Let's see this:

$R_{empty}=\frac{1\ lake}{10\ weeks}$ which implies that this rate empties 0.1 of the lake per week, thus, $R_{empty}=0.1/week$ .

Using the same idea, we can obtain that the filling rate of the river is:

$R_{river}=\frac{1\ lake}{20\ weeks} = 0.05 /week$

Since both rates are acting at the same time, the total rate of flowing water (either in or out the lake) would be given by:

$R_{total}=R_{empty}+R_{river}\\R_{total}= -0.1 + 0.05=-0.05/week$ , which means that the lake is being empty at a rate of -0.05 week and using the rule of three: