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Do students that are "Greek" (those who belong to a sorority/fraternity) have a tendency to be more involved in student governme

balu736 [363]

Answer:

Option B is correct.

The alternative hypothesis is given Mathematically as

Ha: pA - pB > 0

Step-by-step explanation:

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis takes the other side of the hypothesis; that there is indeed a significant difference between two proportions being compared. It usually confirms the the theory being tested by the experimental setup.

For this question, we want to test if students who are "Greek" (those who belong to a sorority/fraternity) have a tendency to be more involved in student government events than students who are "Not Greek" by checking the proportion of each group of students that turn out to vote in the student government elections.

If the proportion of Greek students that turn out to vote in the student government elections = pA

And

The proportion of non-Greek students that turn out to vote in the student government elections = pB

And the difference between them is given as

μ₀ = pA - pB

The theory to be tested that pA > pB, would constitute the alternative hypothesis and the null hypothesis would say that either the proportions are equal or proportion of non-greek students that turn out to vote is more than the proportion of Greek students that turn out to vote in the student government elections.

Mathematically,

The null hypothesis would be that

H₀: μ₀ = pA - pB ≤ 0

or

H₀: pA = pB

And the alternative hypothesis would be that

Hₐ: μ₀ = pA - pB > 0

or

Hₐ: pA > pB

Thereby, confirming the theory to be tested.

Hope this Helps!!!

3 0

3 years ago

Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f

Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

$P(A) = 0.1*0.8 + 0.25*0.2 = 0.13$

Probability that a student is foreign and undergraduate:

10% of 80%. So

$P(A \cap B) = 0.1*0.8 = 0.08$

What is the probability that the student is an undergraduate?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154$

0.6154 = 61.54% probability that the student is an undergraduate

8 0

3 years ago

Simplify this ratio completely 24/16<br>

Bas_tet [7]

Answer:

3/2 or 1.5

Step-by-step explanation:

24/16 = 12/8

12/8 = 6/4

6/4 = 3/2

So, if you want fraction it's 3/2 and decimal is 1.5

5 0

3 years ago

Please help asap im super confused<br> Which is the equation for BC?

Aloiza [94]

Points on BC:
(-5, 5) and (0,1)
Slope = (5-1)/(-5-0)
Slope = -4/5

y = mx + c
y = -4/5x + c

at point (0,1)
1 = -4/5(0) + c
c = 1

y = -4/5x + 1
5y = -4x + 5
4x + 5y = 5 (Answer D)

6 0

3 years ago

An equivalent equation has been written by multiplying the second equation by 2.

AVprozaik [17]

its -5 so it is A,( -19/2, -5)

7 0

3 years ago