![\ \ \ 5 \ (-\frac{1}{5} a = 10 - b) \\ + (2a = 5b -20) \\ \\ a = 30](https://tex.z-dn.net/?f=%5C%20%5C%20%5C%205%20%5C%20%28-%5Cfrac%7B1%7D%7B5%7D%20a%20%3D%2010%20-%20b%29%20%5C%5C%20%2B%20%282a%20%3D%205b%20-20%29%20%5C%5C%20%5C%5C%20a%20%3D%2030)
5× the first equation + the second equation will give an equation of 'a' to its value.
You would subtract, 22 - -11.
22 + 11 = 33.
The range is 33 degrees.
30% decrease because it’s all about subtract
Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
Answer:
The table that represents a linear function is (2,7),(4,9), (6,11), (8,13)