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3 years ago

Heyo can i get help?

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

Answer: C y=1/3x

Step-by-step explanation:

All Y-values in the table are 1/3 of the corresponding X-value. To check: 3/1=1, 6/3=2, 9/3=3

LenaWriter [7]3 years ago

7 0

Answer:

c is right

Step-by-step explanation:

because 1 is 1/3 of 3,2 is 1/3 of 6, and 3 is 1/3 of 9

brainlest pls

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Alissa emptied her piggy bank for disney world. She had $7.70. if she had 10 pennies, twice as many times as quarters, and 1/2 a

Tju [1.3M]

Answer:

She has 20 quarters.

Step-by-step explanation:

Alissa emptied her piggy bank for Disney world. She had $7.70.

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3 years ago

Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at

Dafna1 [17]

Answer:

$\huge\boxed{ \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1}}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

conic sections
PEMDAS

<h3>tips and formulas:</h3>

$\sf hyperbola \:equation : \\ \sf \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1$
vertices of hyperbola:(±a,0) and (0,±b) if reversed
$\sf \: asymptotes : \\ y = \pm\frac{b}{a} x$

<h3>given:</h3>

vertices: (0,±10)
the hyperbola equation is inversed since the vertices is (0,±10)
asymptotes: $\pm \frac{5}{6}x$

<h3>let's solve:</h3>

the asymptotes are in simplest and we know b is ±10

according to the question

$y = \sf \frac{5 \times 2}{6 \times 2} x \\ y = \frac{10}{12} x$

therefore we got

a=12
b=10

note: the equation will be inversed

let's create the equation:

$\sf substitute \: the \: value \: of \: a \: and \: b : \\ \sf \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1$

3 0

3 years ago