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The given point (-3/5 , y) lies in the third quadrant.
It is also given that the point lies on a unit circle.
For a point (x,y) lying on a unit circle a and y are defined as:
x = cos θ
y = sin θ
So, we can say for the point (-3/5 , y) the value -3/5 is equal to cos θ
sec θ is the reciprocal of cos θ.
So, sec θ = -5/3
Using Pythagorean identity we can first find sin θ.
Since the point lies in 3rd quadrant, both sin and cos will be negative.
So, now we can write:
Answers:
sec θ = -5/3
cot θ = 3/4
It is also given that the point lies on a unit circle.
For a point (x,y) lying on a unit circle a and y are defined as:
x = cos θ
y = sin θ
So, we can say for the point (-3/5 , y) the value -3/5 is equal to cos θ
sec θ is the reciprocal of cos θ.
So, sec θ = -5/3
Using Pythagorean identity we can first find sin θ.
Since the point lies in 3rd quadrant, both sin and cos will be negative.
So, now we can write:
Answers:
sec θ = -5/3
cot θ = 3/4