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pshichka [43]
3 years ago
6

If a water tank already contains 55 gallons of water when baxter begins to fill it and water is flowing in at a rate of 8 gallon

s per minute what would the linear equasion for that be?
Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

I think it would be 55+8x. I hope this helps. :)

Step-by-step explanation:

55 gallons of water

8 gallons per minute

It would be 55 gallons (the original amount in the tank) plus 8 gallons per minute. (8x)

x = how many minutes the tank is being filled up more.

so if you were to fill up the tank another 5 minutes, the equation would be 55+8(5)

55+40

95 would be the answer.

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Let p(x)=x^3+15x^2-8x+2. What is the remainder when p(x) is divided by x-2?
Oduvanchick [21]

Answer:

Step-by-step explanation:

Using synthetic division, the zeros goes into the box, which would be -1

-1  |  1  -3  -1  24

           -1   4   -3

       1  -4   3   21

The remainder is 21

4 0
3 years ago
Math factors and multiples review urgent need help
Assoli18 [71]

Answer:

11

Step-by-step explanation:

add 30 then 42 then 18 and divide it in to as many possible

4 0
3 years ago
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Describe IN WORDS how you would solve the equation: 4 + x = -9
vlada-n [284]

Step-by-step explanation:

4 + x = -9

x = -9 +4

x = - 5

-x = -5

x = 5

3 0
3 years ago
Find the maximum and minimum values of the objective function f(x, y) and for what values of x and y they occur, subject to the
Lady_Fox [76]

Given that <em>f(x, y)</em> is a linear function, and the constraints themselves are also linear, it follows that the vertices of the feasible region are the sites of extrema of <em>f(x, y)</em>. So just find where each boundary line intersects with another line, and check the value of <em>f(x, y)</em> at each intersection.

We have

• <em>x</em> = 0 and <em>y</em> = 0   ===>   (0, 0)

• <em>x</em> = 0 and 2<em>x</em> + 7<em>y</em> = 70   ===>   <em>y</em> = 10   ===>   (0, 10)

• <em>y</em> = 0 and 8<em>x</em> + 4<em>y</em> = 136   ===>   <em>x</em> = 17   ===>   (17, 0)

• 2<em>x</em> + 7<em>y</em> = 70 and 8<em>x</em> + 4<em>y</em> = 136   ===>   (14, 6)

At these points, we respectively get

• <em>f</em> (0, 0) = 0

• <em>f</em> (0, 10) = 60

• <em>f</em> (17, 0) = 34

• <em>f</em> (14, 6) = 64

Then max <em>f(x)</em> = 64 at (14, 6) and min <em>f(x)</em> = 0 at (0, 0).

5 0
3 years ago
Please help
DedPeter [7]

Answer:

$53750

Step-by-step explanation:

Sam deposit $12500 every year which grows at a simple interest of 3% and we have to calculate the total sum after 4 years.

If Sam deposit $x with r% simple interest then the principal will grow after 4 years to x[1 + \frac{4r}{100}]

Again, for the second year $x investment with r% simple interest will grow to  x[1 + \frac{3r}{100}].

Now, the third year $x investment with r% simple interest will grow to  x[1 + \frac{2r}{100}]

And finally the fourth year $x investment with r% simple interest will grow to  x[1 + \frac{r}{100}]

Therefore, the total sum becomes

x[1 + \frac{4r}{100}] + x[1 + \frac{3r}{100}] + x[1 + \frac{2r}{100}] + x[1 + \frac{r}{100}]

= 4x + \frac{10 \times r \times x}{100}

= 4x + \frac{rx}{10}

So, in case of Sam the sum will be = 4 \times 12500 + \frac{3 \times 12500}{10} = $53750

7 0
3 years ago
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