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Stella [2.4K]
3 years ago
13

During halftime of a football ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 5 fee

t with an initial upward velocity of 64 feet per second. The​ T-shirt is caught 37 feet above the field. How long will it take the​ T-shirt to reach its maximum​ height? What is the maximum​ height? What is the range of the function that models the height of the​ T-shirt over​ time?
Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0
It takes 2 seconds to reach a maximum height of 69 feet, and the range is [5, 69].

The equation is of the form
h(t) = -16t² + v₀t + h₀, where -16 is the gravitational constant, v₀ is the initial velocity, and h₀ is the initial height.  Using the values from our problem, we have:

h(t) = -16t² + 64t + 5

To find the maximum height, we find the vertex.  The first step in this is to find the axis of symmetry, which is given by -b/2a:

-64/2(-16) = -64/-32 = 2

This is our value for t, so it takes 2 seconds to reach the maximum.  Substituting this into our function, we have
h(2) = -16(2²) + 64(2) + 5 = -64 + 128 + 5 = 64 + 5 = 69

This is the maximum height.

The range of heights goes from 5 to 69, inclusive, or [5, 69].
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3 years ago
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He stepped back 59.71 feet.

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Start by making 2 triangles. One has 68 degrees as the acute angle at the base of the triangle and the other has 41 degrees as the acute angle at the base of the triangle. The side opposite of said angle on both triangles will be 80, the height of the tree. You're solving for the bottom (horizontal) side for both triangles.

For the triangle with an acute base angle of 68, the formula to solve for the horizontal side is tan(68) = 80/x.

Get x by itself to get 80/tan(68) = x

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