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Stella [2.4K]
3 years ago
13

During halftime of a football ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 5 fee

t with an initial upward velocity of 64 feet per second. The​ T-shirt is caught 37 feet above the field. How long will it take the​ T-shirt to reach its maximum​ height? What is the maximum​ height? What is the range of the function that models the height of the​ T-shirt over​ time?
Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0
It takes 2 seconds to reach a maximum height of 69 feet, and the range is [5, 69].

The equation is of the form
h(t) = -16t² + v₀t + h₀, where -16 is the gravitational constant, v₀ is the initial velocity, and h₀ is the initial height.  Using the values from our problem, we have:

h(t) = -16t² + 64t + 5

To find the maximum height, we find the vertex.  The first step in this is to find the axis of symmetry, which is given by -b/2a:

-64/2(-16) = -64/-32 = 2

This is our value for t, so it takes 2 seconds to reach the maximum.  Substituting this into our function, we have
h(2) = -16(2²) + 64(2) + 5 = -64 + 128 + 5 = 64 + 5 = 69

This is the maximum height.

The range of heights goes from 5 to 69, inclusive, or [5, 69].
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Rectangle OPEN has diagonals intersecting at S. If m∠ENP=42 find m∠ EON, m∠ONP, m∠OSP, and m∠PSE
poizon [28]

Answer:

m∠EON = 48°

m∠ONP = 48°

m∠PSE = 90°

4 0
3 years ago
Write the equivalent expression for 6x + 5y + 7x
Oksana_A [137]
I'm pretty sure it is d, you are combining the terms which is the same thing.
6 0
3 years ago
Read 2 more answers
Can someone please help me?
storchak [24]
5lbs=8.25
/5    /5
1lbs=1.65


6 0
3 years ago
FEE
frozen [14]

Answer:

The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

  • y+2=\frac{3}{4}\left(x+4\right)
  • 3x - 4y = -4

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the line

3x - 4y = 7

writing in the slope-intercept form

4y = 3x - 7

dividing both sides by 4

4y/4 = 3/4x - 7/4

y = 3/4x - 7/4

Now, comparing with the slope-intercept form of the line equation

y = 3/4x - 7/4

The slope of the line m = 3/4

We know that parallel lines have the same slopes.

Therefore, the slope of the parallel line is: 3/4

now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)

y+2=\frac{3}{4}\left(x+4\right)

Thus, the equation in the point-slope form of the line equation is:

y+2=\frac{3}{4}\left(x+4\right)

Simplifying the equation

y+2=\frac{3}{4}\left(x+4\right)

Subtract 3 from both sides

y+2-2=\frac{3}{4}\left(x+4\right)-2

y=\frac{3}{4}x+1

Multiplying the equation by 4

4y = 3x + 4

3x - 4y = -4

Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

  • y+2=\frac{3}{4}\left(x+4\right)
  • 3x - 4y = -4
7 0
3 years ago
Consider the geometric sequence 16, 8, a, 2, b, ... (a) Write down the common
Artist 52 [7]

Find the common ratio by dividing.

16 / 8 = 2

8 / a = 2

2 / b = 2

The common ratio is 2.

Since we need to find the values of a and b, use the common ratio to solve for them.

8 / 2 = 4 (a)

2 / 2 = 1 (b)

Now, we know that first 5 terms.

We can solve for the 8th term using the previous terms and the common ratio.

6th term: 1 / 2 = 0.5

7th term: 0.5 / 2 = 0.25

8th term: 0.25 / 2 = 0.125

Part A: 2

Part B: a = 4, b = 1

Part C: 0.125

Best of Luck!

3 0
3 years ago
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