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cricket20 [7]
3 years ago
13

PLEASE I NEED HELPP !!

Mathematics
2 answers:
QveST [7]3 years ago
4 0

Answer:

D 9 softball tickets for $72

Step-by-step explanation:

72/9=8

Akimi4 [234]3 years ago
4 0

Answer:

The answer is D.

Step-by-step explanation:

You divide 72 by 9. Hope this helps!!! Please mark me brainliest and have a good rest of your day!!!

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Please help no links please
allsm [11]

Answer:

C

Step-by-step explanation:

The secant- tangent angle MLK is half the difference of the intercepted arcs, that is

\frac{1}{2} (KN - KM) = 70° ( multiply both sides by 2 to clear the fraction )

KN - KM = 140°

KN - 61° = 140° ( add 61° to both sides )

KN = 201° → C

8 0
3 years ago
which of the following graphs shows a negative linear relationship with a correlation coefficient r close to -0.5
Yuri [45]

Answer:

go awnser My questtion i posted and the awnser is B

Step-by-step explanation:

5 0
3 years ago
sarita is selling lemonade in 300 millileter bottles. she made two batches of lemonade. each batch made 4.6liters of lemonade. h
saul85 [17]
200 ml will be left over
5 0
3 years ago
Find the value of x in the triangle
miss Akunina [59]

Answer: \sqrt{52}

Step-by-step explanation:

a^2 +b^2 = c^2

4^2 = 16

6^2 = 36

16+36=52

c^2=52

c=\sqrt{52}

5 0
3 years ago
Read 2 more answers
Question 1- Whats the derivative of: A) f(x)= 4 cos(x) + ln(x+1)<br> B) f(x)= sec(x) X tg(x)
Kryger [21]

The derivatives for this problem are given as follows:

a) f^{\prime}(x) = -4\sin{x} + \frac{1}{x + 1}

b) f^{\prime}(x) = \sec{x}\tan^{2}{x} + \sec^3{x}.

<h3>What is the derivative of the sum?</h3>

The derivative of the <u>sum is the sum of the derivatives</u>.

In this problem, the function is:

f(x) = 4\cos{x} + \ln{(x + 1)}

Using a derivative table for the derivatives of the cosine and the ln, the derivative of the function is:

f^{\prime}(x) = (4\cos{x})^{\prime} + (\ln{(x + 1)})^{\prime}

f^{\prime}(x) = -4\sin{x} + \frac{1}{x + 1}

What is the product rule?

The derivative of the product is given as follows:

(f(x) \times g(x))^{\prime} = f^{\prime}(x)g(x) + g^{\prime}(x)f(x)

In this problem, we have that:

  • f(x) = \sec{x}, f^{\prime}(x) = \sec{x}\tan{x}.
  • g(x) = \tan{x}, f^{\prime}(x) = \sec^2{x}.

Hence the derivative is:

f^{\prime}(x) = \sec{x}\tan^{2}{x} + \sec^3{x}.

More can be learned about derivatives at brainly.com/question/2256078

#SPJ1

4 0
2 years ago
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