Now the first mechanic takes 4 days to do the job, so after he has worked for 1 day only, he has done 1/4 of the whole thing.
the second mechanic can do it in 6 days, so after 1 day only of work, he has done 1/6 of the whole thing.
the third mechanic can do it in 8 days, so after a day, he has done 1/8 of the total work.
now, if they all three work together, after 1 hour has gone by, the first mechanic has done 1/4 of the whole thing, the second mechanic has done 1/6 of it, and the last one, has done 1/8.
let's say it took all three working together "t" days, that means after 1 hour of work, they all combined have done 1/t of the whole thing, thus
A.
lxl=7
x=7 x=-7 (Take two cases, one as the others side negative and the other as positive)
B.
l2xl=32
2x=32 2x=-32
x=16 x=-16
C.
lx+7l=10
x+7=10 x+7=-10
x=3 x=-17
D.
lxl=53.1
x=53.1 x=-53.1
Answer:
answer: 4.5
Step-by-step explanation:
2x=3+6
2x=9
x=9/2
x=4.5
Here is my table of points:
3.3333333333333333333
repeating