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3 years ago

A housepainter mixed 2 gallons of blue paint with

Mathematics

1 answer:

maria [59]3 years ago

8 0

Answer:

Option D: 6:12 is correct answer.

Step-by-step explanation:

We can find the simplest form of ratio to compare it with the given ratios.

According to given statement,

The ratio is:

$No.\ of\ Blue\ Paint\ Gallons: No.\ of\ red\ paint\ gallons\\2:4\\Simplifying\\1:2$

Now we will check if the given options can be simplified to 1:2

So,

Option A:

$8:12\\2:3$

Option B:

$8:24\\1:3$

Option C:

$3:5$

Option D:

$6:12\\1:2$

As we can see that 6:12 can be simplified to 1:2 which is same as 2:4 so it will make the same shade of purple.

Hence,

Option D: 6:12 is correct answer.

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Find the sale price of each item. Round to two decimal places when necessary.

Bond [772]

Answer:

Sale Price: 276.25

Step-by-step explanation:

The original price of the item is $325 and the markdown is 15% off.

So, all you have to do is find out what 15% of $325, which it's 48.75, and subtract that from $325 to get your final sale price, which is $276.25.

7 0

2 years ago

What is the slope G(8,1) & H(8,-6).

Gennadij [26K]

M=slope=(y2-y1)/(x2-x1)=(-6-1)/(8-8)=-7/0 which is technically undefined. This is just a vertical line namely:

x=8 (you can think of a vertical line as having infinite slope)

6 0

2 years ago

If two triangles are congruent which of the following statements must be true

Sati [7]

The statement which must be true are Options B, C and D

which are the triangles have the same size and shape, the corresponding sides of the triangles are congruent and the corresponding angles of the triangles are congruent.

<h3>What are congruent triangles?</h3>

Congruent triangles are triangles that have corresponding sides, angles which are all equal in measure.

They can be rotated and turned to be look be identical.

Thus, the statement which must be true are Options B, C and D

which are the triangles have the same size and shape, the corresponding sides of the triangles are congruent and the corresponding angles of the triangles are congruent.

The complete question is

If two triangles are congruent which of the following statements must be true? CHECK ALL THAT APPLY

A. The triangles have the same size but not the same shape.

B. The triangles have the same size and shape

C. The corresponding sides of the triangles are congruent.

D. The corresponding angles of the triangles are congruent.

Learn more about congruent triangles here:

brainly.com/question/1675117

#SPJ1

4 0

1 year ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .