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Romashka-Z-Leto [24]
3 years ago
14

Use the expanded form find the perimeter of 10cm and 18cm² in square shape

Mathematics
1 answer:
TiliK225 [7]3 years ago
3 0
The answer for the area would be 180cm and the perimeter would be 56cm
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I dont know what letter but its 12i^2+i+6

Step-by-step explanation:

cross multiply

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Manolo and Annalisa make handbags. Manolo made 16 handbags the first day and 12 each day after that. Annalisa made 8 the first d
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b and c

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3 years ago
Read 2 more answers
A group of 59 randomly selected students have a mean score of 29.5 with a standard
algol [13]

Answer:

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

\bar X = 29.5 represent the sample mean

\mu population mean  

s= 5.2 represent the sample standard deviation

n=59 represent the sample size  

Confidence interval

The confidence interval for the true mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=59-1=58

The Confidence interval is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical value is t_{\alpha/2}=1.671

Now we have everything in order to replace into formula (1):

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

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3 years ago
RATIO AND PROPORTION<br> 1st correct answer is marked brainliest
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Answer:

2:9         4:8

8:3         24:6

9:7          3:2

18:15      6:6

18:12     12:16

10:40    5:9

12:16     6:7

12:36     12:18

45:15     4:5

those in bold are the answer

3 0
3 years ago
Read 2 more answers
A square has an area of 16x^2 square inches. If the sides of the square were to increase by 2 units, what is the new area of the
kykrilka [37]

Answer:

16x² + 64x + 64

Step-by-step explanation:

Given

A = 16x²

Increasing the sides by 2, substitute x = x + 2 into A

A = 16(x + 2)² ← expand factor using FOIL

   = 16(x² + 4x + 4 ) ← distribute

   = 16x² + 64x + 64

4 0
3 years ago
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