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Lera25 [3.4K]
2 years ago
14

Evaluate: 3x^2 + y when x=1 and y=-3 *

Mathematics
1 answer:
Sliva [168]2 years ago
4 0

Answer:

0

Step-by-step explanation:

x=1 and y=-3

so 3x^2 + y = 3*1^2 + (-3)

= 3* 1 -3

=0

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Answer:

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From the question we are told that

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Generally the sample  proportion can be mathematically evaluated as

     \r p = \frac{ upper \ limit  + lower \ limit }{2}

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Given that the confidence level is  98% then the level of significance can be mathematically evaluated as

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        Z_{\frac{\alpha }{2} } =  2.33

Generally the minimum sample size is evaluated as

      n  =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 *  \r p (1- \r p )

     n  =[ \frac { 2.33}{0.1} ]^2 *  0.475(1- 0.475 )

     n  =135

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