Answer:
d. 1.5%
Step-by-step explanation:
Given - The track and field coach records Ian's 400-meter race times during three practices.
Practice 1 2 3
Time (s) 63 60 58
To find - How much greater was the percent of change from Practice 1 to Practice 2 than from Practice 2 to Practice 3? Round to the nearest tenth.
a.
7.9%
b. 4.8%
c. 3.3%
d. 1.5%
Proof -
% change from Practice 1 to Practice 2 change =
%
=
% = - 4.761904762 %
⇒% change from Practice 1 to Practice 2 change = - 4.762 %
Now,
% change from Practice 2 to Practice 3 change =
%
=
% = - 3.334 %
⇒% change from Practice 2 to Practice 3 change = - 3.3334 %
So,
- 4.461904762% - (- 3.3334%) = -4.461904762 + 3.3334 % = -1.4285 % ≈ 1.5%
∴ we get
Value = 1.5%
The correct option is - d. 1.5%
Answer:
See explanation:
Step-by-step explanation:
Let a and b be integers.
Sum means addition.
So we are trying to figure out what a+b equals.
It could result in as 0, negative, or positive.
a+b is 0 when a and b are of opposite values. Example: 5+(-5) or -5+5 is 0 because 5 and -5 are opposite values.
a+b is positive when both a and b are positive. Example 5+3=5.
a+b is positive when |a|>|b| and a is positive. Example: 5+(-3)=2 since |5|>|-3| and 5 is positive.
a+b is positive when |a|<|b| and b is positive. Example: -3+5=2 since |-3|<|5| and 5 is positive.
a+b is negative when both a and b are negative. Example: -5+(-3)=-8.
a+b is negative when |a|>|b| and a is negative. Example: -5+3=-2 since |-5|>|3| and -5 is negative.
a+b is negative when |a|<|b| and b is negative. Example: 3+(-5)=-2 since |3|<|-5| and -5 is negative.
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>

.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>

.
Answer:
10000000000000000000000,
the next number: 1-934028049747284
that's all
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Step-by-step explanation: