What is 32,020.2o rounded to the nearest tenth
2 answers:
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Answer:
The width and length of rectangle is 12.728 m
Step-by-step explanation:
Let the length of the rectangle = L
let the width of the rectangle = W
The subjective function is given by;
F(p) = 2(L + W)
F = 2L + 2W
Area of the rectangle is given by;
A = LW
LW = 162 ft²
L = 162 / W
Substitute in the value of L into subjective function;
Take the second derivative of the function, to check if it will given a minimum perimeter
Determine the critical points of the first derivative;
df/dw = 0
L = 162 / 12.728
L = 12.728 m
Therefore, the width and length of rectangle is 12.728 m