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3 years ago

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Mathematics

1 answer:

Tamiku [17]3 years ago

5 0

Answer:

22.) 2.0651

23.) 4.231

Step-by-step explanation:

22.) Substitute values into equation

(x)(y) + 2 =

(2.1)(0.031) + 2 = 2.0651

23.) Substitute values into equation

(y) + (x)2

(0.031) + (2.1)2 = 4.231

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jonny [76]

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4 years ago

What is the sum of the favorable and unfavorable probabilities?

Leya [2.2K]

Step-by-step explanation:

Step 1:

Let a coin is flipped. My choice is Heads and my unfavorable becomes Tails.

Here the probability of getting heads is (1/2) and getting tails is (1/2).

Step 2:

Hence, If we add both of it we will get the resultant sum as 1 only.

(1/2) + (1/2) = 1

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4 years ago

Read 2 more answers

What's 2+2 I really need this answer plz help ASAP

kondor19780726 [428]

Answer:

Step-by-step explanation:

2+2=4

6 0

3 years ago

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Divide and answer in simplest form: 4/5 ÷ 2

mestny [16]

Answer:

2/5

Step-by-step explanation:

4/5*1/2=4/10=2/5

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4 years ago

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Records show that the average number of job applications received per week is 5.9. Find the probability of 6 job applications re

german

Answer:

16.05% probability of 6 job applications received in a given week.

Step-by-step explanation:

When you have the mean during an interval, you should use the Poisson distribution.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Records show that the average number of job applications received per week is 5.9.

This means that $\mu = 5.9$

Find the probability of 6 job applications received in a given week.

This is P(X = 6).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 6) = \frac{e^{-5.9}*(5.9)^{6}}{(6)!} = 0.1605$

16.05% probability of 6 job applications received in a given week.

6 0

4 years ago