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Paladinen [302]
2 years ago
5

What's 2+2 I really need this answer plz help ASAP

Mathematics
2 answers:
nordsb [41]2 years ago
8 0

Answer:

4

Step-by-step explanation:

2+2=4

If you need anymore help you can tell me

kondor19780726 [428]2 years ago
6 0

Answer:

4

Step-by-step explanation:

2+2=4

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Two communications companies offer calling plans. With Company X, it costs 30¢ to connect and then
tensa zangetsu [6.8K]
<h3>Answer:  n+15</h3>

=======================================================

Explanation:

  • n = number of minutes
  • cost of company X = 3n+30
  • cost of company Y = 2n+15

To find out how much more company X charges, we subtract the two cost expressions

CompanyX - CompanyY = (3n+30)-(2n+15) = 3n+30-2n-15 = n+15 which is the final answer.

--------------

An example:

Let's say you talk on the phone for n = 20 minutes.

Company X would charge you 3n+30 = 3*20+30 = 90 cents

Company Y would charge you 2n+15 = 2*20+15 = 55 cents

The difference of which is 90-55 = 35 cents.

If you plugged n = 20 into the n+15 expression we got, then n+15 = 20+15 = 35 matches up with the previous 35 cents.

This example helps confirm the answer. I'll let you try out other examples.

8 0
2 years ago
Here's a more clear picture for you guys sorry the last one was fuzzy.
sergeinik [125]
RhTh + RsTs = 180    (Rh = 70, Rs=20 , Th = Ts)
70Th + 20Th = 180
90 Th = 180
Th = 2
since Th = Ts,
thus, Ts = 2


6 0
3 years ago
Whats .4 (repeating) divided by 3/8??
hichkok12 [17]
.444444 divided by 3/8 = 0.01666666666
6 0
3 years ago
Read 2 more answers
Fernell and Dabney shared the driving
Agata [3.3K]

Answer:

15 hours

Step-by-step explanation:

Given:

Fernell's speed v_F= 50 mph

Dabney's speed v_D= 64 mph

Denote:

D_F - distance covered by Fernell

D_D - distance covered by Dabney

t_F - Fernell's time

t_D - Dabney's time

1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

t_F=t_D+3

2. If Fernell covered 18 miles less than Dabney, then

D_D-D_F=18

Use formula D=t\cdot v

D_D=v_D\cdot t_D\Rightarrow D_D=64\cdot t_D\\ \\D_F=v_F\cdot t_F\Rightarrow D_F=50\cdot (t_D+3)

Subtract from the first equation the second equation and equate it to 18:

64t_D-50(t_D+3)=18\\ \\64t_D-50t_D-150=18\\ \\14t_D=168\\ \\t_D=12\ \text{hours}

t_F=t_D+3=12+3=15\ \text{hours}

5 0
3 years ago
A 54-kg jogger is running at a rate of 3 m/s. What is the kinetic energy of the jogger? A. 18 J B. 81 J C. 162 J D. 243 J
Wewaii [24]

   

\displaystyle\bf\\\text{\bf kinetic energy}=\frac{mv^2}{2}=\frac{54\times3^2}{2}=27\times9=\boxed{\bf243~J} \\\\\text{\bf Correct answer: D.}



4 0
3 years ago
Read 2 more answers
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