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3 years ago

Pleaseeeeeewe helpppppp

Mathematics

2 answers:

vitfil [10]3 years ago

5 0

Answer:B

Step-by-step explanation:

GalinKa [24]3 years ago

5 0

B. is the answer hope this helps :)

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-12y = 60<br> Check your solution

iragen [17]

Answer:

negaative 5

Step-by-step explanation:

8 0

3 years ago

If E be an event, then P(E) + P(not E) = _____________.

Yuki888 [10]

Answer:

Step-by-step explanation:

If P(E) = p

Then P(not E) = 1-p

3 0

3 years ago

solve the system of linear equations algebraically using the elimination method: 3x+y=19 and 4x+3y=26

Molodets [167]

-3(3x+y=19)
4x+3y=26

-9x-3y=-57
4x+3y=26

-5x=-31
x=6.2 substitute x into the equation:

3(6.2)+y=19
18.6+y=19
y=.4

(6.2,.40)

5 0

3 years ago

Which shows the following expression using positive exponents?

Hitman42 [59]

Answer:

1. option B is correct i.e., $\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. option D is correct i.e., $\frac{a^3b^4}{ab^2}$ .

3. option B is correct i.e., $\frac{n^{10}}{16m^{6}}$ .

Step-by-step explanation:

1. Since the given equation is:

$\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}$

As we know that $a^{-x}=\frac{1}{a^x}$

So, the given equation can be represented as:

$\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. Given equation is:

$\frac{a^3b^{-2}}{ab^{-4}}$

As we know that $a^{-x}=\frac{1}{a^x}$

so the given equation can be represented as:

$\frac{a^3b^4}{ab^2}$ .

3. Given equation is:

$(\frac{4mn}{m^{-2}n^6})^{-2}$

by using the properties $a^{-x}=\frac{1}{a^x}$ ,

and $a^x\times a^y=a^{x+y}$

$(\frac{4mn}{m^{-2}n^6})^{-2}$

= $(\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}$

= $(\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}$

= $(\frac{4n^{-5}}{m^{-3}})^{-2}$

= $\frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}$

= $\frac{n^{10}}{16m^{6}}$ .

which is option B.

5 0

3 years ago

Read 2 more answers

The number 1953125 is equal to 5^9. explain how the information above informs you that 1953125 is not a square number

ValentinkaMS [17]

If 1953125 is a square number, then $1953125=n^2,~n\in\mathbb{N}$

By what's given, $1953125=5^9\Rightarrow n^2=5^9\Rightarrow n=5^{4.5}=625\sqrt{5}$

But $n=625\sqrt{5} \notin\mathbb{N}$ , therefore, our assumption that 1953125 is a square number is wrong.

4 0

3 years ago