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Oksanka [162]
2 years ago
8

I need help for question 17 in my big ideas math homework, it says "Use the figure to find the measures of the numbered angles."

Mathematics
1 answer:
Dafna1 [17]2 years ago
7 0

Answer:

can you show a pic tell me in the comments

Step-by-step explanation:

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If f(x)=3x-7, find f(x)=2
Arisa [49]

Answer:

x = 2

Step-by-step explanation:

8 0
3 years ago
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At 8:00 a.m. the temperature outside in Juneau, Alaska was -16.5 . By noon the temperature had increased by 15.25 . What is the
adelina 88 [10]

It would be -1.25 degrees at noon.

3 0
3 years ago
Which of the following is equivalent to 2-47
lara31 [8.8K]

Answer:

45

Step-by-step explanation:

2 minus 47 equals 45 if that's what your talking about

7 0
2 years ago
This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}

where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)
=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
=\dfrac23+\ln\dfrac89
4 0
3 years ago
For simple linear regression, y = β0 + β1x + u, which one of the following statements is true?
RSB [31]

Answer:

Option a) u is called the "error term". It is the error we make in prediction

Option d) x is called the independent variable because x is independent from y and u.

Step-by-step explanation:

We are given the following information in the question:

y = \beta_0 + \beta_1x + u

where y is the dependent variable, x is the independent variable.

\beta_0: It is the value of y when x is zero, that is y-intercept.

\beta_1: It is the coefficient of x in predicting the dependent variable y.

u is the error term.

  • An error term represents the margin of error.
  • It refers to the sum of the deviations within the regression line, that is the difference between the predicted value and the observed value of y.

Thus, Option A) u is the error term and Option D)  x is called the independent variable because x is independent from y and u are the correct answer.

6 0
3 years ago
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