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bekas [8.4K]
3 years ago
8

the length of a rectangle is 13 centimeters less than its width. What are the dimensions of the rectangle if it’s area is 114 sq

uare centimeters?

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

w = 19

L = 6

Step-by-step explanation:

L = w - 13

a = lw

114 = w(w - 13)

114 = w² - 13w

w² - 13w - 114

(w - 9) (w + 6)

w ≠ -6 (a length cannot be negative)

w = 19

L = 19 - 13

L = 6

tigry1 [53]3 years ago
5 0
here is ur answer dear frnd

let width = x cm

so length = x - 13 cm

According to question ,

Area = length × breadth

114 = x( x-13)

114= x^2 - 13 x

x^2 -13x - 114 =0

x^2 -19x + 6x -114 =0

x(x-19) + 6(x- 19)= 0

(x-19)(x+6)= 0

take x - 19 = 0

so x = 19

take x+6 = 0

that gives x= -6 ( not possible)

so width = 19 cm

and length = 19- 13 = 6 cm
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22% of all resumes received by a corporation for a management position are from females. 18 resumes will be received tomorrow.
Vladimir79 [104]

Answer:

5.80% probability that exactly 1 resume will be from females.

Step-by-step explanation:

For each resume received by the corporation, there are only two possible outcomes. Either they are from a female, or they are not. The probability of a resume received being from a female is independent from other resumes. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

22% of all resumes received by a corporation for a management position are from females.

This means that p = 0.22

18 resumes will be received tomorrow.

This means that n = 18

What is the probability that exactly 1 resume will be from females?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{18,1}.(0.22)^{1}.(0.78)^{17} = 0.0580

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3 0
3 years ago
How do you solve this problem?
jekas [21]
Very nice problem. You should look up the history of this question. It has a very long one having to do with mirrors made between 50 BC and 50 AD.

Step One
Find AB, BC, AC
Before beginning this problem, I'm going to arbitrarily name 
c = AB
a = BC
b = AC It just makes the calculations easier.

AB = radius of the large circle - radius of the medium circle = 20.62 - 8.04 = 12.58
BC = Radii of the two smaller circles added together = 8.04 + 7.35 = 15.39
AC = Radius of the large circle - Radius of the small circle = 20.62 - 7.35 = 13.27

So
a = 15.39
b = 13.27
c = 12.58

Step Two
Find Angle A or <BAC
a^2 = b^2 + c^2 - 2*b*c * Cos(A)
15.39^2 = 12.58^2 + 13.27^2 - 2 * 12.58 * 13.27 * Cos(A)
236.852 = 158.26 + 176.1 -  333.87 * Cos(A)
236.852 = 334.4 - 333.87*Cos(A)
-97.55 = - 333.87 *  Cos(A) 
-97.55 / -333.87 = Cos(A)
0.2922 = cos(A)
A = cos-1(0.2922)
A = 73.01 degrees

Step Three
Just to see if you understand what was done, I'll give you the givens for finding c, and the answer and you can work through the calculations to see if your answer agrees with mine. If it doesn't PM me.
c = 12.58
b = 13.27
a = 15.39

12.58^2 = 13.27^2 + 15.39^2 - 2*13.27*15.39*Cos(C)
C = 51.42

Step Four
Find <B
Every triangle has 180 degrees so
B = 180 - <A - C
B = 180 - 51.42 - 74.01
B = <54.57. 
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