Tanner walks 42 kilometers each morning. How many meters does he walk each morning?

worty [1.4K]

The answer is 0.6.

9.24÷15.4=0.6

7 0

3 years ago

gizmo_the_mogwai [7]

Answer:

1.7 miles.

Step-by-step explanation:

We have been given that Mark runs back and forth on a football field for a total of 3000 yards.

Since we know that 1 mile equals to 1760 yards. To find the number of miles Mark ran we will divide 3000 yards by number of yards in one mile (1760).

$\text{ Mark ran}=\frac{3000\text{ yards}}{1760\frac{\text{yards}}{\text{mile}}}$

$\text{ Mark ran}=\frac{3000\text{ yards}}{1760}\times \frac{\text{miles}}{\ext{yards}}$

After cancelling out yards from numerator and denominator we will get,

$\text{ Mark ran}=\frac{3000}{1760} \text { miles}}$

$\text{ Mark ran}=1.7045454545454545\text{ miles}}\approx 1.7\text { miles}}$

Therefore, Mark ran 1.7 miles on the football field.

5 0

3 years ago

Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .