If you visualize the problem, there are two concentric circles, the pool, and the pool plus the walkway. So, we have to subtract the area of these two concentric circles to find the walkway.
Bigger circle: Pool plus walkway
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diameter = 18 + 4(2) -- this is because there is 2 ft of walkway at each far end
diameter = 26 ft
Area = pi*(26/2)^2
Area = 530.93 ft2
Smaller circle:pool
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diameter = 18 ft
Area = pi*(8/2)^2
Area = 50.27 ft2
Area of walkway
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A = 530.93 - 50.27
A = 480.66 ft2
Then the cost would be
Cost = $4.25 * 480.66
Cost = $2,042.81
__ 5 __, __
the first would be 2
after 5 is 8
after 8 is 11
Hope this helps!!!
120+x+16+x=180
2x+ 136=180
2x=44
X= 22
<B= 22
Answer:
tita = 0 , 180, 270, 360. ( tita = 0 ≤ x ≤ 360).
Step-by-step explanation:
sin tita + sin ^2 tita = 0
sin tita( sin tita + 1) = 0
sin tita = 0, - 1.
For angles between 0 and 360 inclusive sin = 0 gives 0, 180 and 360 degrees. The angle whose sine is -1 is 270 degrees.
tita = 0 , 180, 270, 360.
is standard form
