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3 years ago

12

PLEASE HELP ASAP! I have reposted this 2 times and no one will help me.:( please answer all 4 thank you so much!! i need this do

ne in an hour!!!

1 answer:

erik [133]3 years ago

5 0

Answer:

5. DE

6. 3 cm

7. 20 in

8. ΔDCF

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Justify whether the solution makes sense.

Zigmanuir [339]

Answer:

They are identical triangles.

Step-by-step explanation:

Angles in a triangle add up to 180 degrees.

The triangle with 39 and 90 has a missing angle of 51 degrees, and the triangle with 51 and 90 vice versa.

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2 years ago

Read 2 more answers

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

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3 years ago

Draco Malfoy or the Weasley twins?

tekilochka [14]

Answer:

DRACO MALFOY FOR SURE

Step-by-step explanation:

7 0

2 years ago

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Simplify give ur answer in index form.

kherson [118]

$\frac{( {j}^{4} \: \times \: {j}^{8}) ^{3} }{( {j}^{9} \: \div \: {j}^{2}) ^{2} }$

First we calculate the product of the denominator.

$\frac{( {j}^{12}) ^{3} }{( {j}^{9} \: \div \: {j}^{2}) ^{2} }$

Then we calculate the quotient of the numerator.

$\frac{( {j}^{12}) ^{3} }{( {j}^{7}) ^{2} }$

We multiply the exponents of the expression.

$\frac{ {j}^{36} }{ {j}^{14} }$

We divide.

$\boxed{ \bold{ {j}^{22} }}$

<h3><em><u>MissSpanish</u></em></h3>

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2 years ago

What is −14 − (+6) =

zepelin [54]

Answer:

-20

Step-by-step explanation:

it basically -14-6

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3 years ago