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fredd [130]
2 years ago
5

Given the sets: A = {1, 2, 3, 6, 7, 9} and B = {2, 4, 6, 7, 8}. Find (A*upside down U*B).

Mathematics
1 answer:
brilliants [131]2 years ago
4 0

Answer:

the answer would be {2,7,6}

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Their 15,000 kids in the multipurpose room.there is only 16 rows with 5 seats in each.how many kids will not have a seat to sit
sp2606 [1]

Answer: 14,920 kids

Step-by-step explanation:

15,000-(16×5)=x

15,000-80=x

14,920=x

8 0
2 years ago
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Given log5 3=0.6826 and log5 8=1.2920, evaluate the expressions<br><br> Please help!?
gulaghasi [49]

Answer:

a) 1.3652

b) 1.3906

Step-by-step explanation:

a) log5 9 = log5 3² = 2log5 3 = 2(0.6826) = 1.3652

b) log5 75/8 = log5 75 - log5 8 = log5 3×25 - log5 8=

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2 years ago
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3) The length of JM is 9x + 6 units, the length of JK is
Vlada [557]

Answer:

JM = 60 units

Step-by-step explanation:

Given:

JM = 9x + 6

JK = 5x

KM = 3x + 12

JK + KM = JM (segment addition postulate)

(5x) + (3x + 12) = (9x + 6) (substitution)

Solve for x

5x + 3x + 12 = 9x + 6

Collect like terms

5x + 3x - 9x = -12 + 6

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Divide both sides by -1

x = 6

JM = 9x + 6

Plug in the value of x

JM = 9(6) + 6

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JM = 60 units

3 0
3 years ago
Are 3y+3 and 9(y+1/3) equivalent
vovangra [49]

Answer:

no

Step-by-step explanation:

3y+3 doesnt equal 9y+3

5 0
2 years ago
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In a zoo there are 17 more monkeys than lions and 30 more lizards than lions. If there were 151 monkeys, lions and lizards in to
kvv77 [185]
If the amount of monkeys is m, lions is a, and lizards is b, then a+b+m=151, 17+a=m (since there are 17 more monkeys than lions), and 30+a=b. Substituting those values in (17+a=m and 30+a=b), we have 30+17+a+a+a=151=47+3a. Subtracting 47 from both sides, we get 104=3a. Next, we can divide both sides by 3 to get 104/3=a (the number of lions), 104/3+17=the number of monkeys, and 104/3+30=the number of lizards. Somehow we end up with a fraction (not a whole number), so there are 2/3rds of monkeys floating around using this logic.


8 0
2 years ago
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