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-BARSIC- [3]
3 years ago
13

In sugar beet, there is 21% of sugar. How much sugar beet do you need in order to get 7,413 tons of sugar?

Mathematics
2 answers:
lara [203]3 years ago
8 0

Answer:

35,300

Step-by-step explanation:

I do rsm, but i forgot how to do it

quester [9]3 years ago
7 0
Pretty sure its 35,300

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If we start at the point (1,0) and travel once around the unit circle, we travel a distance of 2 pi units and arrive back where
PolarNik [594]

Answer:

-1

Step-by-step explanation:

We evaluate \sin(2\pi+3\pi/2)

In 2\pi+3\pi/2, 2\pi is a complete revolution and is the same as 0. So we have

\sin3\pi/2 = \sin(\pi+\pi/2)

One \pi is a half revolution, putting the point at (-1, 0). \pi/2 is a quarter of a revolution. A quarter circle from (-1, 0) anticlockwise is (0, -1).

The sine is the y-coordinate of a point along a unit circle.

Hence, \sin(2\pi+3\pi/2)=-1

3 0
3 years ago
Mr. Torres has a class of 17 students. He can spend $24 on each student to buy math supplies for the year. He first buys all of
scZoUnD [109]

Answer:

She has a class of 17 kids. At $24 each, she can spend 17*$24 = $408. Since she spent $125.36, she has $408 - $125.36 = $282.64 left to spend.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Simplify the following
slamgirl [31]
The answer for the question is D. 3m
5 0
3 years ago
Read 2 more answers
Adam has 3 coins in his pocket and they are all different from each other. Ben has 3 coins in his pocket and they are all the sa
Elenna [48]

Answer:

The possible coins are:

P = penny = $0.01

N = nickel = $0.05

D = dime = $0.10

Q = quarter = $0.25

H = half dollar = $0.50

We know that Adam has 3 coins in his pocket, and all of them are different, then the money that Adam has can be represented with (A + B + C)

Behn has 3 coins, and all of them are the same, then if his coin has a value X, he has a total of 3*X

We know that Adam has half as much money as Ben, this can be written as:

(A + B + C) = 3*X/2

The easier way to solve this, is to play with different values of X, and see if we can find the values of A, B and C.

For example, if X = $0.10

then:

(A + B + C) = $0.10*(3/2) = $0.15

We can find 3 different value of coins for this equation? No, we cant, so X = $0.10 is also discarded.

if x = $0.50 then:

(A + B + C) = (3/2)*$0.50 = $0.75

Here we could have:

A = $0.50

B = $0.25

then: A + B = $0.75

But we still have the coin C.

If we take X = $0.25 then:

(A + B + C) = (3/2)*$0.25 = $0.375

We could round the right part to $0.40

then the coins in the left part would be:

A = $0.25

B = $0.10

C = $0.05

A + B + C =  $0.25 + $0.10 +  $0.05 = $0.40

This is a strech, but is the only thing we can make with the given problem.

5 0
3 years ago
Heather is a cashier. She can ring up 121212 customers in 999 minutes. At this rate, how many minutes does it take her to ring u
DerKrebs [107]
Would it be 121212/999 then times by 444, which would be 212.3x444 to give a final answer of 53872 minutes
8 0
3 years ago
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