Can someone find the perimeter of this shape? ill give brainliest if ur right
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D- The new graph would be steeper than the original graph, and the y- intercept would shift up 3 units.
The purple line is y=-5x + 2
The pink line is y = -7x + 5
Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
