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mixer [17]
3 years ago
10

In a circle, an angle measuring pie over 2 radians intercepts an arc of length 1 pie. Find the

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

2 units

Step-by-step explanation:

We are given that

Angle ,\theta=\frac{\pi}{2}radian

Length of an arc=\pi

We have to find the radius of circle in simples form.

We know that

\theta=\frac{l}{r}

Where l=Length of arc

r=Radius of circle

Using the formula

\frac{\pi}{2}=\frac{\pi}{r}

r=\frac{2\times \pi}{\pi}

r=2units

Hence, the radius of the circle=2 units

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masya89 [10]

Answer:

Chad is incorrect

Step-by-step explanation:

Since A is in quadrant 2, we know the x must be negative and y is positive. Therefore, if we add a negative sign in front of both x and y, x will become positive, and y will become negative. However, in the 3rd quadrant, both x and y must be negative, which is not the case here. Hence, Chad is wrong.

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3 years ago
ASAP I really need help please!
slava [35]

Answer:

I can't see the fine details of the image displaying the weights of the bags but I would assume the heaviest bag is 2(3/4) pounds, being Bag C. The lightest bag is most likely Bag B, being 2(3/8) pounds.

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3 years ago
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Jenna bought books for $3 each and a game for $5. She spent a total of $26. How many books did she buy?
OleMash [197]

Answer:

she bought 7 books and 1 game. 1.)each=multiplication. 2.)and= addition.

Step-by-step explanation:

3.)26-5(the game)=21 divide by 3=7 books

4.)p-5=x divided by 3

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3 years ago
If the diameter of a circle is 6 inches, what is the area?
Bezzdna [24]
The answer is a. 3π in.2
5 0
3 years ago
The population of a type of local frog can be found using an infinite geometric series where a one equals 84 and the common rati
kodGreya [7K]
A=84 and r=1/5

Since r, the common ratio squared is less than one, the sum will converge to a limit.  Rule:  if  r^2<1 infinite series converges, otherwise it diverges.

Since the sum of any geometric sequence is:

s(n)=a(1-r^n)/(1-r)

And if r^2<1, (1-r^n) becomes 1-0=1 as n approaches infinity.

So whenever r^2<1 the sum of the infinite series is just:

s(n)=a/(1-r)

Since a=84 and r=1/5 this infinite series has a sum of:

s(n)=84/(1-1/5)

s(n)=84/(4/5)

s(n)=5(84)/4

s(n)=105
5 0
3 years ago
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