Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
The answer is B.
This is because <span>any angle formed by two chords is equal to half the sum of intercepted arcs.</span>
The solutions of the equations are -1.3 and -7.7
Step-by-step explanation:
The quadratic formula of solving the quadratic equation
ax² + bx + c = 0, where a, b and c are constant is:
To solve the quadratic equation by using the quadratic formula
1. Find the values of a , b and c from the equation
2. Substitute the values of a , b and c in the quadratic formula
3. Find the two values of x
∵ x² + 9x + 10 = 0
∴ a = 1 , b = 9 and c = 10
∵ 
∴ 
∴ 
∴ x = -1.3
∵ 
∴ 
∴ 
∴ x = -7.7
The solutions of the equations are -1.3 and -7.7
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Answer:
$(0.50+0.75n)
$6.50
Step-by-step explanation:
Please see attached picture for full solution.