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N76 [4]
3 years ago
6

Anybody wanna join my clan

Biology
2 answers:
miskamm [114]3 years ago
7 0

Answer: mmmmm no

Explanation:

Georgia [21]3 years ago
7 0

Answer:

.

Explanation:

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Imagine that a plant cell has a damaged large central vacuole that is not functioning. which statement best describes how damage
Serjik [45]

Answer:

The correct answer is D

Explanation:

The primary function of the large central vacuole in a plant cell is to maintain turgor pressure against the cell wall of the plant. This vacuole also perform other functions such as storage (water and other nutrients) and waste disposal. When this vacuole is damaged in plant cells, the cells may no longer be able maintain turgor pressure and store materials (water inclusive). Also, <u>If the cell cannot store raw materials via the large central vacuole, the chloroplast will lack the raw materials required for photosynthesis</u>.

8 0
3 years ago
Would an Egyptian pyramid that is 4500 years old be considered a fossil?
lara [203]

An Egyptian pyramid that is 4500 years old will be considered as a fossil in this scenario.

<h3>What is a Fossil?</h3>

This is defined as trace of an animal or plant of a past geologic age that has been preserved in Earth's crust.

Since it has been discovered that the egyptian pyramid contains thousands of marine fossils then it can be generally referred to as a fossil.

Read more about Fossil here brainly.com/question/11829803

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8 0
2 years ago
Yo i need help cs this due soon
attashe74 [19]
Substitution i believe. There’s nothing deleted
6 0
3 years ago
FASTTTTTTTTT.physical science !! please help
WITCHER [35]

Answer:

The answer is synthesis :)

6 0
3 years ago
The lungs remain inflated because ___________.a. intrapleural pressure is exactly equal to atmospheric pressure b. intrapleural
kkurt [141]

Answer:

Option C,  Intrapleural pressure is less than intrapulmonary pressure

Explanation:

During inspiration, the air enters the lungs due to lower pressure in the intrapulmonary or intra-alveolar  than the atmospheric pressure. During quite respiration, the intrapulmonary pressure reduces to a pressure that is 3 mm Hg lower than that of atmospheric pressure. During quiet expiration, the intrapulmonary pressure rises up to a pressure that is 3 mm Hg higher than that of atmospheric pressure. This leads to lack of air in the intrapleural space thereby producing intrapleural pressure which is lesser than that of intrapulmonary pressure.  

This difference in pressure (i.e higher pressure with in the lungs than the atmosphere)  causes lungs to remain attached to the chest wall and hence looks inflated.  

Hence, option C is correct

8 0
3 years ago
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