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3 years ago

14

Suppose a scientist puts a colony of bacteria weighing 1 gram in a large container. Assume that these bacteria reproduce in such

a way that their number doubles every 20 minutes.

1 answer:

DedPeter [7]3 years ago

5 0

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkk

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Given g(x)= -2x+2 and f(x)= 3x^2+4, find (g+f)(-3)

aliina [53]

Answer:

39

Step-by-step explanation:

g(x)= -2x+2 and f(x)= 3x^2+4

(g+f)(-3)

g(-3) = -2(-3) +2 = 6+2 =8

f(-3) = 3 (-3)^2 +4 = 3(9)+4 = 27+4 = 31

(g+f)(-3) = g(-3) + f(-3) = 8+31 = 39

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3 years ago

Write the unit rate and the rate 15 points scored in 4 quarters

Trava [24]

You first divide both numbers by 4 to get one quarter which is the unit, and to get the rate, you divide 15 by 4 also. i got the unit rate is 3.75 points oer quarter.

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3 years ago

Please please please urgent help❤️❤️❤️

Harlamova29_29 [7]

Answer:

its G(2)

Step-by-step explanation:

Gg

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3 years ago

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What is the sum? …………….

aniked [119]

5 over y plus 5. you combine the fractions by finding the common denominator

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3 years ago

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting. It is

yan [13]

Answer:

No, there is not sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting.

This means that the null hypothesis is:

$H_{0}: \mu = 434$

It is believed that the machine is underfilling the bags.

This means that the alternate hypothesis is:

$H_{a}: \mu < 434$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

434 is tested at the null hypothesis:

This means that $\mu = 434$

A 9 bag sample had a mean of 431 grams with a variance of 144.

This means that $X = 431, n = 9, \sigma = \sqrt{144} = 12$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{431 - 434}{\frac{12}{\sqrt{9}}}$

$z = -0.75$

P-value of the test:

The pvalue of the test is the pvalue of z = -0.75, which is 0.2266

0.2266 > 0.01, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

7 0

2 years ago