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3 years ago

A student runs 35 m east and then 12 m west. What is the distance run by the

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

5 0

Answer:

A.47 m

Step-by-step explanation:

you a add 35 m east and 12 m west

kirill115 [55]3 years ago

3 0

Answer:

It should be A. 47 m

Step-by-step explanation:

You might be interested in

At the movie theatre, child admission is $5.90

Alik [6]

Let the number of children be c, and the number of adults be a.
c + a = 170 (total number of tickets)
Then the cost of each is: $5.90/child, $9.60/adult:
5.9c + 9.6a = 1269.40 (total sales)
Solving as 2 simultaneous equations, we first transform the first equation:
a = 170 - c
Substitute into the 2nd equation:
5.9c + 9.6(170 - c) = 1269.40
Solving gives c = 98, and a = 170 - 98 = 72. This means that 72 adult tickets were sold that day.

5 0

4 years ago

A 9 ft. ladder leans against the side of a house. The bottom of the ladder is 6 ft. from the side of the house. How high is the

erica [24]

Answer:

15 ft

Step-by-step explanation:

I'm not sure but I think u add them together to get ur answer

hope it helps

5 0

2 years ago

Mark sold x pens for $2 each. He received less than $80 from the sale. a. Write an inequality for the number of pens sold.

Ganezh [65]

Answer:

x <40

Step-by-step explanation:

The income from the pens is 2*x

He made less than 80

2x <80

Divide each side by 2

2x/2 < 80/2

x < 40

7 0

3 years ago

A department store wants to know what fraction of its customers in a certain market have store credit cards, and what their aver

bearhunter [10]

Answer:

The 98% confidence interval for the average credit card balance is

(564.04, 635.96).

Step-by-step explanation:

We have to calculate the 98% confidence interval on the average credit card balance.

The sample will consist of the n=30 customers that have credit card.

The sample has a mean of $600 and a standard deviation of $80.

As the population standard deviation is estimated from the sample standard deviation, we will use a t statistic.

The degrees of freedom are:

$df=n-1=30-1=29$

The critical value for a 98% CI and 29 degrees of freedom is t=2.463 (this can be looked up in a t-table).

Then, the margin of error is:

$E=t\cdot s/\sqrt{n}=2.463*80/\sqrt{30}=197.04/5.48=35.96$

Then, the upper and lower bounds of the confidence interval are:

$LL=\bar X-E=600-35.96=564.04\\\\UL=\bar X+E=600+35.96=635.96$

4 0

3 years ago

(8v + 8) (8v^2 + 4v - 8) find the product

mars1129 [50]

Answer:

Answer is below

Step-by-step explanation:

64v^3+96v^2-32v-64

5 0

3 years ago

Read 2 more answers