Answer:all real numbers except 4 and 2
Explanation:The given function is:
f(x) =

Domain of the function is defined as the values of x that can be used to substitute in the function.
We know that any fraction cannot have a zero in its denominator. Because if this happens, then the fraction would be undefined.
This means that in the given function, we cannot substitute with any value for x that makes the denominator a zero.
Now, we will get the zeroes of the denominator as follows:
x² - 6x + 8 = 0
(x-4)(x-2) = 0
either x-4 = 0 ...........> x = 4
or x-2 = 0 .............> x = 2
Based on the above, we can substitute with any value for x excluding 4 and 2.
This means that the domain of the function is any real real number except 4 and 2
Hope this helps :)
Okay so I am going to summarize the work out process because its a lot to
Here we go
1/3 (t) + 3/4 - 2/4 - t = ?
1/2 (simplify )
(1/3 (T)+3/4 - 1/2 - (t) = ?
t (2) / 2
1 - 2(t) / 2 = ?
3/4 (simplify this )
1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?
1/3 (this is re last one you have to simplify)
L (Denominator): 3
R (Denominator): 4
L: [L.C.M] : 4
R: [L.C.M] : 3
Basically , we just switched the dominators around
So, Therefore The of t is -3/16
T = -3/16
Answer:im not sure sorry
Step-by-step explanation:
I have no clue what to answer 9
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<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em>