Answer:
Results:
0.1432
0.0045
0.0905
0.0483
Step-by-step explanation:
Step a:
P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432
Step b:
P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045
Step c:
P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905
Step d:
P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483
As well we get the probability by subtracting a, b and c:
P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482
Y = 2x
y = 2*(-15) = -30 . . . . . selection A is appropriate
For x^3-11x^2+33x+45 , we can make it an equation so <span>x^3-11x^2+33x+45=0. Next, we can find out if -1 or -3 is a factor. If -1 is a factor, than (x+1) is factorable. Using synthetic division, we get
x^2-12x+45
___ ________________________
x+1 | x^3-11x^2+33x+45
- (x^3+x^2)
_________________________
-12x^2+33x+45
- (-12x^2-12x)
______________
45x+45
-(45x+45)
___________
0
Since that works, it's either B or D. We just have to figure out when
</span> x^2-12x+45 equals 0, since there are 3 roots and we already found one. Using the quadratic formula, we end up getting (12+-sqrt(144-180))/2=
(12+-sqrt (-36))/2. Since sqrt(-36) is 6i, and 6i/2=3i, it's pretty clear that B is our answer
ST/VT = UT/WT6+14/14 = (x+4)+21/21X= 20*21/14 - 21x=420/14-25X=30-25x=5
