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3 years ago

Find the surface area of the cylinder. Round your answer to the nearest hundredth.

Mathematics

1 answer:

horsena [70]3 years ago

4 0

Answer:

C. 795.45 in^2

Step-by-step explanation:

The formula for the surface area of a cylinder is ...

SA = 2πr^2 +2πrh = 2πr(r +h)

For r=6 and h=15.1, the surface area is ...

SA = 2π(6)(6 +15.1) = π(12)(21.1) = 253.2π

SA ≈ 795.45 . . . . square inches

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4 years ago

what is the surface area of a rectangular prism that has a height of 5cm a width of 10cm and a depth of 4cm

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4 years ago

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3

Nat2105 [25]

Question:

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1/2 inches long. The scale of the floor plan is 1/4 inch = 1 foot. What is the actual length of Hector’s room?

Answer:

The actual length of Hector room is 14 foot

Solution:

Given that, On the floor plan, his bedroom is 3 inches wide and $3\frac{1}{2}$ inches long

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$\frac{1}{4} \text{ inch} = 1 \text{ foot }$

Therefore,

$1 \text{ inch } = 4 \text{ foot}$

To find: Actual length of floor

From given question,

$length = 3\frac{1}{2} \text{ inches}$

Converting the mixed fraction to improper fraction,

$length = \frac{2 \times 3 + 1}{2} = \frac{7}{2} \text{ inches }$

Since, 1 inch = 4 foot

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3 years ago

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3 years ago

A particular battery claims to have a mean life of 400 hours with a standard deviation of 30 hours. Approximately what percent o

Svetach [21]

Using the normal distribution, it is found that 25.14% of the batteries will last more than 420 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, we have that the mean and the standard deviation are given, respectively, by:

$\mu = 400, \sigma = 30$ .

The proportion of the batteries will last more than 420 hours is one subtracted by the p-value of Z when X = 420, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{420 - 400}{30}$

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

1 - 0.7486 = 0.2514.

0.2514 = 25.14% of the batteries will last more than 420 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

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2 years ago