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2 years ago

Find the volume A. 150 cm3 B. 180 cm3 C. 90 cm3 D. 90 cm2

Mathematics

1 answer:

valina [46]2 years ago

6 0

Answer:

268 in²

Step-by-step explanation:

The surface area is basically the entire area of the figure. You can do it multiple ways, but this is how I did it. I found the area of each side and added them all together. There are three sets of identical sides. First, we'll calculate the area of the side with lengths 10" and 8".

10 · 8 = 80

There are two of these sides, so currently we have 80 + 80.

Next, the area of the sides with lengths 8" and 3". These are the sides at the top and bottom.

8 · 3 = 24

So to our equation we now have 80 + 80 + 24 +24.

For the final two sides, we have the dimensions 10" and 3".

10 · 3 = 30

To our equation, we add this to get 80 + 80 + 24 + 24 + 30 +30.

Add all these numbers together for 268.

In the correct form, we add the square symbol to show that we are talking about area. The answer is 268 in². Good luck :D

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If 1,000 students take a test that has a mean of 40 minutes, a standard deviation of 8 minutes, and is normally distributed, how

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500 because in a normal distribution 50% of the total falls below the mean

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3 years ago

Read 2 more answers

Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

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2 years ago

It is estimated that there are 10^20 grains of sand on a beach in Florida in April. The beach is heavily eroded by tourists over

lyudmila [28]

$\bf \textit{how much is }\frac{1}{100}\quad of \quad 10^{20}?\implies \stackrel{\textit{one hundredth}}{\cfrac{1}{100}}\cdot 10^{20}\implies \cfrac{1}{10^2}\cdot 10^{20}
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10^{-2}\cdot 10^{20}\implies 10^{-2+20}\implies 10^{18}
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1,000,000,000,000,000,000~grains$