Question

Please help and solve; big points 3/2 ∜(2(x-6)^3 )+4=16

Answer 1

Answer:

x ≈ 18.7

Step-by-step explanation:

This is a big equation, so let's break it down a bit.

$\frac{3}{2} \sqrt[4]{(2(x-6) ^3 )} +4=16$

Let's start by isolating the radical which is x.

So subtract 4 from both sides :

$\frac{3}{2} \sqrt[4]{(2(x-6) ^3)}$$=12$

Now multiply both sides by 2 to get rid of the fraction :

$3\sqrt[4]{(2(x-6)^3)} = 24$

Now divide both sides by 3 to get rid of the number out of the poly root :

$\sqrt[4]{2(x-6) ^3}$$=8$

Now take both sides of the equation to the power of 4 :

$2x^3 - 36x^2+216x-432=4096$

And lastly, solve :

$x = 18.69920$ which is rounded up to $x$ ≈ $18.7$