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xxMikexx [17]
3 years ago
10

Please help and solve; big points 3/2 ∜(2(x-6)^3 )+4=16

Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

x ≈ 18.7

Step-by-step explanation:

This is a big equation, so let's break it down a bit.

\frac{3}{2} \sqrt[4]{(2(x-6) ^3 )} +4=16

Let's start by isolating the radical which is x.

So subtract 4 from both sides :

\frac{3}{2} \sqrt[4]{(2(x-6) ^3)}=12

Now multiply both sides by 2 to get rid of the fraction :

3\sqrt[4]{(2(x-6)^3)} = 24

Now divide both sides by 3 to get rid of the number out of the poly root :

\sqrt[4]{2(x-6) ^3}=8

Now take both sides of the equation to the power of 4 :

2x^3 - 36x^2+216x-432=4096

And lastly, solve :

x = 18.69920 which is rounded up to x ≈ 18.7

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