A'(1,-2)
B'(1,-3)
C'(-1,-3)
D'(-1,-2)
x-intercept is 6, coordinates (6,0)
y-intercept -4, coordinates (0,-4)
gradient= y1-y2/x1-x2= 0-(-4)/6-0= 4/6= 2/3 or 0.667 (3.s.f.)
Answer:
100 km squared
Step-by-step explanation:
Front : 14
Back : 14
Top : 28
Bottom : 28
Side : 8
Side : 8
Surface area : 100 km squared
Hope this helps!
Answer:
If the maximum of function r(x) and t(x) occur at the same point c in domain P = max(r(x)+t(x)) = M+N
In general P ≤ M+N
Step-by-step explanation:
If the maximum of function r(x) and t(x) occur at the same point c in domain then M=r(c) and N=t(c) So in this case P = max(r(x)+t(x)) = M+N
In general P ≤ M+N
by definition of maximum
r(x)≤M,t(x)≤N for all x in domain
=> r(x)+t(x)≤M+N for all x in domain
=> max(r(x)+t(x)) <= M+N
=> P ≤ M+N
Thus we get in general the relationship is P ≤ M+N
