Answer:
Area of the trapezium ABDE = 30 cm²
Step-by-step explanation:
Area of a trapezium = 
Here, 
and 
are the parallel sides of the trapezium
h = Distance between the parallel sides
From the picture attached,
ΔCAE and ΔCBD are the similar triangles.
So by the property of similarity their sides will be proportional.
CE = 
CE = 12 cm
Therefore, DE = CE - CD
DE = 12 - 8 = 4 cm
Now area of trapezium ABDE = 
= 
= 30 cm²
Therefore, area of the trapezium ABDE = 30 cm²
Answer:
37.2
Step-by-step explanation:
when you turn the small triangle LMN to its right angle to cover the right angle of KLM, you find that they are similar triangles.
therefore the corresponding side lengths are at the same ratio.
LM/KM = MN/LN
LM = 24
MN = 13
we can get LN via Pythagoras of the small triangle
LN² + MN² = LM²
LN² + 13² = 24²
LN² = 24² - 13² = 576 - 169 = 407
LN = sqrt(407) = 20.174241
now back to our main problem
24/KM = 13/sqrt(407)
24×sqrt(407)/13 = KM = 37.2
Answer:
The dimensions are 5 and 10 inches
Step-by-step explanation:
The area is 50 square inches and the length is twice the width. 10 is the length, which is two times 5. 10 times 5 is 50.
The length is 10 and the width is 5.
Caterer two charges 550 for hall rental plus $40 per person
Multiply all terms in the first equation by 2 and all terms in the second by 3.
You should obtain:
6x + 16y = 34
-6x + 27y = 9
------------------
43y =43, and so y = 1. Subbing 1 for y in the first eq'n, we get
3x + 8(1) = 17, or 3x = 9, or x = 3.
The solution is (3, 1).
