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2 years ago

13

Mason took out an $800 loan from the bank. At the end of 5 years, he pays back the principle, plus $120 simple interest. What is

the interest rate? Show your work

1 answer:

kirza4 [7]2 years ago

6 0

Answer:

3% or 0.03

Step-by-step explanation:

120/5=24

24 is 3% of 800.

We can assume that 800 is 100 percent.

That means 1 percent is 8.

24 is 3 percent.

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Let A be a 5 × 4 matrix with a pivot in each column. Is A invertible? Why or why not?

erastova [34]

Answer:

Matrix A is not invertible.

Step-by-step explanation:

Invertible matrix are those matrix which are square matrix or non singular matrix.

For any matrix to be invertible, matrix should be non singular i.e. det(x) $\neq$ 0.

But for the question given above we cannot find determinant of matrix A as it is not square matrix. so inverse of given matrix does not exist. so it is not possible to have non trival solutions.

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2 years ago

A production line produces 12 cd players every 4 hr. how many players can it produce in 37 hr?

zloy xaker [14]

Since its not an even number it would be 432

8 0

3 years ago

Given f(x)=3x-2 and g(x)=5x, what is f(x)•g(x)

Natasha2012 [34]

F(x)·g(x) = (3x-2)(5x) = 15x^2 -10x

6 0

2 years ago

If triangle RST is within Quadrant 4 and cos R= √3/2, what is the value of cotR

Nesterboy [21]

Answer:

CotR = -√3

Step-by-step explanation:

In the 4th quadrant, sin is negative;

Since Cos R = √3/2,

Adjacent = √3

Hypotenuse = 2

Get the opposite;

opp^2 = 2^2 -(√3)^2

opp^2 = 4 - 3

opp^2 = 1

Opp = 1

Get sinR

Sin R = opp/hyp

SinR= -1/2

CotR = cosR/sinR

CostR = (√3/2)/(-1/2)

CotR = √3/2* -2/1

CotR = -√3

6 0

2 years ago

Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2

Temka [501]

Answer:

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

$a_n=a_1+(n-1)d$

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

$a_1=-10\\d=-2$

substitute

$a_n=-10+(n-1)(-2)$

$a_n=-10-2n+2$

$a_n=-2n-8$

so

<u><em>Find the first ten terms</em></u>

$a_1=-10$

For n=2 ----> $a_2=-2(2)-8=-12$

For n=3 ----> $a_3=-2(3)-8=-14$

For n=4 ----> $a_4=-2(4)-8=-16$

For n=5 ----> $a_5=-2(5)-8=-18$

For n=6 ----> $a_6=-2(6)-8=-20$

For n=7 ----> $a_7=-2(7)-8=-22$

For n=8 ----> $a_8=-2(8)-8=-24$

For n=9 ----> $a_9=-2(9)-8=-26$

For n=10 ----> $a_1_0=-2(10)-8=-28$

The sequence is

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

5 0

2 years ago