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anastassius [24]
3 years ago
9

Explain how you can write a fraction equivalent to 1/4

Mathematics
2 answers:
Juliette [100K]3 years ago
4 0

Answer:  2/8  

Step-by-step explanation: becau

lina2011 [118]3 years ago
3 0

Here, we have to write a fraction equivalent to \sf{ \dfrac{1}{4}}.

  • To find a fraction equivalent to the given fraction, we multiply a same number with the denominator and the numerator of the given fraction.

Multiply 2 with the numerator and the denominator of the fraction.

→ \sf{ \dfrac{1}{4} = \dfrac { 1 \times 2}{ 4 \times 2} }

→ \sf{ \dfrac{1}{4} = \dfrac { 2}{ 8} }

So, a fraction equivalent to \sf{ \dfrac{1}{4}} is \sf \red{ \dfrac{2}{8}}.

Similarly, we can multiply with another numbers (ex : 3,4,5,6) with numerator and the denominator of the given fraction to find the fractions equivalent to the given fraction.

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PLEASE ANSWER GIVING 30 POINTS
Orlov [11]

Answer:

this is only 15points but ok

Step-by-step explanation:

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If gasoline sells for $1.25 per gallon, how much would 3 3/5 gallons cost? express your answer as a decimal
diamong [38]
3 3/5 gallons of gasoline would cost $4.50

This is because when you multiply 1.25 by 3 you get a product of 3.75.
Then, you multiple 1.25 with 3/5 and get a product of 0.75.
Add the two together, and you receive a sum of 4.50.
So, the cost for 3 3/5 gallon is $4.50.
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One earthquake has MMS magnitude 3.9. If a second earthquake has 120 times as much energy (earth movement) as the first, find th
Anna71 [15]

Answer:

The right answer is "5.9". A further solving is provided below.

Step-by-step explanation:

The given values are:

Initial Magnitude,

M₁ = 3.9

Let Second magnitude be M₂.

Now,

⇒  M_2-M_1=log(\frac{l_2}{l_1} )

On substituting the values, we get

⇒  M_2-3.9 = log (120)

On putting the value of "log 120", we get

⇒  M_2-3.9=2.079

On adding "3.9" both sides, we get

⇒  M_2-3.9+3.9=2.079+3.9

⇒                    M_2=5.9

7 0
3 years ago
420 hg = _____ cg<br> please help me
Reika [66]

Answer:

420 hg = __4200000___ cg

Step-by-step explanation:

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8 0
3 years ago
We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood fol
jarptica [38.1K]

Answer:

The required confidence inteval = 94.9%.

Step-by-step explanation:

Confidence interval: Mean ± Margin of error

Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).

i.e.  Mean + Margin of error = 42.969               (i)

Mean - Margin of error = 36.191                    (ii)

Adding (i) and (ii), we get

2Mean =79.16\\\\\Rightarrow\ Mean= 39.58

Margin of error = 42.969-39.58             [from (i)]

= 3.389

Margin of error = t^* \dfrac{\sigma}{\sqrt{n}}

here n= 25 , \ \sigma=8.25

i.e.

3.389=t^*\dfrac{8.25}{5}\\\\\Rightarrow\ t^* = \dfrac{3.389}{1.65}\\\\\Rightarrow\ t^* =2.0539 \

Using  excel function 1-TDIST.2T(2.054,24)

The required confidence inteval = 94.9%.

7 0
3 years ago
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