There is a profit of $39.7.
It is given that there 100 tickets costing $10 per ticket.
You must look first for the probability of the 4 prizes which are $475, $195, $30, and no prize.
P ($475 prize) = 1/100 or 0.01
P ($95 prize) = 2/100 or 0.02
P ($30 prize) = 4/100 or 0.04
P (No prize) = 100/100 – 1+2+4/100 =93/100 .93
Expected gain or loss is computed by: (P(x)* n)
E= (475-10)*.01 + (95-10)*0.02 + (30-10)* 0.04 + (-10)*.93
= 46.5 + 1.70 + 0.8 – 9.3
E = 39.7
There is a profit of $39.7.
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Answer:
4x+2
and 22
Step-by-step explanation:
2x-5+6+2x-5+6=4x+2
if x=5, so perimeter 4(5)+2=20+2=22
Answer:
Step-by-step explanation:
Answer:
I won't stop the line for a half hour break.
Step-by-step explanation:
<u>Proportions</u>
One quantity A is said to be proportional to other B if A can always be obtained by multiplying or dividing B by any constant number. Numbers {4,8,12} are proportional to {2,4,6} because they can be computed as twice their value
.
There is a situation described in the problem where we need to know if there will be enough time to produce the 900 toasters (the goal for the day) when the assembly line is stopped by half an hour.
Actual time: 2:00 pm
Final time: 5:00 pm
Rate of production: 2 toasters/minute
Actual production: 560 toasters
Updated goal: 900-560 = 340 toasters
Those 340 toasters must be produced in the remaining 3 hours (180 minutes) of work. If the assembly line stops for half an hour (30 minutes), there will be only 150 minutes to finish the goal production. At a rate of 2 toasters/minute, there will be 2*150 = 300 toasters produced. But we need to produce 340 more toasters, so that break cannot be granted or we'll be 40 toasters under goal.
It the line keeps producing for 180 minutes, it would produce 2*180 = 360 toasters, 20 more than the goal.
Note: The maximum break time that can be granted is 20/2 = 10 minutes
division problem
In a division problem, the number being divided into pieces is the dividend. The number by which the dividend is divided is called the divisor. And the answer to the division problem is the quotient.
