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katen-ka-za [31]

3 years ago

15

Find the radius of the button. radius: __ in.

1 answer:

Marat540 [252]3 years ago

8 0

Answer:

1 3/4 in

Step-by-step explanation:

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

are there any other considerations that should be taken into account when trying to fit a giant tv into your car

FrozenT [24]

The width and height of the tv as well as the length and width of the back of your car

6 0

3 years ago

217x + 99 = 25 what is the answer

EleoNora [17]

217x+99=25 217x=25-99 217x= -74 X=-74/217

4 0

4 years ago

Where could point E be if and D is between E and B?

Artemon [7]

Answer:

It would be to the left of the whole equation.

Step-by-step explanation:

3 0

3 years ago

What is the volume of this right prism? 1200 in³ 1800 in³ 2040 in³ 3600 in³ Right triangular prism. The height of the prism is l

zhenek [66]

Answer: It Is 1800 in³

Step-by-step explanation:

7 0

2 years ago